Answer:
solution:-a homogenous mixture of two or more substances in relative amounts that can be varied continuously up to what is called the limit of solubility.
solute:-is a substance, usually a solid, that is dissolved in a solution, which is usually a liquid.
solvent:-substance, ordinarily a liquid, in which other materials dissolve to form a solution.
polar molecule:-is a molecule in which one end of the molecule is slightly positive, while the other end is slightly negative.
Nonpolar molecules occur when electrons are shared equal between atoms of a diatomic molecule or when polar bonds in a larger molecule cancel each other out.
concentration refers to the amount of a substance in a defined space.
Explanation:
Argon, it's a noble gas in the last group on the periodic table.
The density of the product gas mixture is 5.39 g/L
Explanation:
<u>Given:</u>
Temperature after the reaction = 
C
Pressure in the container = 1.65 atm
The ideal gas equation PV = nRT
<u>To find:</u> Density of the product gas mixture
<u>Step 1:</u>
Molarity (M) = P/(RT)
![\[M=\frac{P}{R T}\]$M=\frac{1.65 \mathrm{atm}}{\left(0.08206 \frac{L \cdot a t m}{m o l . K}\right)(298.15 K)}$](https://tex.z-dn.net/?f=%5C%5BM%3D%5Cfrac%7BP%7D%7BR%20T%7D%5C%5D%24M%3D%5Cfrac%7B1.65%20%5Cmathrm%7Batm%7D%7D%7B%5Cleft%280.08206%20%5Cfrac%7BL%20%5Ccdot%20a%20t%20m%7D%7Bm%20o%20l%20.%20K%7D%5Cright%29%28298.15%20K%29%7D%24)
M = 0.0674 mol/L
<u>Step 2: </u>
The product of the given reaction is 
. Its molar mass is
1S x 32.066 g/mol = 32.066 g/mol
3O x 16 g/mol = 48 g/mol
Adding both we get 80.066 g/mol
Therefore the density of the product gas mixture is 
= 5.39 g/L
Answer:
D. 6.3 x 10-5 mol/L NaOH
Explanation:
Alizarin yellow is an indicator that is yellow when pH < 10.1. In the same way, thymol blue is blue when pH > 9
That means the pH of the solution is between 9 - 10.1
Any acid as HCl could have a pH of these.
The solution of 3.2x10⁻⁴M NaOH has a pH of:
pOH = -log[OH-] = 3.49
pH = 14-pOH = 10.51. The pH of the solution is not 10.5
Now, the solution of 6.3x10⁻⁵M NaOH has a pH:
pOH = -log[OH-] = 4.2
pH = 14-pOH = 9.8
The pH of the solution could be 9.8. Right option is:
<h3>D. 6.3 x 10-5 mol/L NaOH</h3>
