Deacceleration causing reverse of speed impact on the body of the frame causing reverse of shockwave.
Answer:
Vf = 73.4 m/s
Explanation:
This is the case of vertical motion where we have to find the final velocity of the penny when it hits the ground. We can use 3rd equation of motion to find the final velocity:
2gh = Vf² - Vi²
where,
g = 9.8 m/s²
h = height = 275 m
Vf = Final Velocity = ?
Vi = Initial Velocity = 0 m/s
Therefore,
2(9.8 m/s²)(275 m) = Vf² - (0 m/s)²
Vf = √5390 m²/s²
<u>Vf = 73.4 m/s</u>
M=F/A
Which means 30 divided by 5 m/s is 6kg(mass)
Answer:
Original speed of the mess kit = 4.43 m/s at 50.67° north of east.
Explanation:
Let north represent positive y axis and east represent positive x axis.
Here momentum is conserved.
Let the initial velocity be v.
Initial momentum = 4.4 x v = 4.4v
Velocity of 2.2 kg moving at 2.9 m/s, due north = 2.9 j m/s
Velocity of 2.2 kg moving at 6.8 m/s, 35° north of east = 6.9 ( cos 35i + sin35 j ) = 5.62 i + 3.96 j m/s
Final momentum = 2.2 x 2.9 j + 2.2 x (5.62 i + 3.96 j) = 12.364 i + 15.092 j kgm/s
We have
Initial momentum = Final momentum
4.4v = 12.364 i + 15.092 j
v =2.81 i + 3.43 j
Magnitude

Direction

50.67° north of east.
Original speed of the mess kit = 4.43 m/s at 50.67° north of east.