A car starts to move from rest and covers a distance of 360m in one minute. Calculate the acceleration of the car.
1 answer:
<h2>The acceleration of car is 0.2 ms⁻²</h2>
Explanation:
When the car moves , the distance covered is calculated by the relation
S = u t + a t²
In this question u = 0 , because car was at rest initially
Thus S = a t²
here S is displacement and a is the acceleration of car
Therefore 360 = a ( 60 )²
Because time taken is one minute or 60 seconds
Therefore a =
or a = 0.2 m s⁻²
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Answer:
0.911 atm
Explanation:
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Therefore, we can apply Gay-Lussac's law, which states that:
"For a fixed mass of an ideal gas kept at constant volume, the pressure of the gas is proportional to its absolute temperature"
Mathematically:
where
p is the gas pressure
T is the absolute temperature
For a gas undergoing a transformation, the law can be rewritten as:
where in this problem:
is the initial pressure of the gas
is the initial absolute temperature of the gas
is the final temperature of the gas
Solving for p2, we find the final pressure of the gas:
Answer:
a) 141.6m
b) 8.4m/s
Explanation:
a) to find the total displacement you use the following formula for each trajectory. Next you sum the results:
hence, the total distance is 141.6m
b) the mean velocity of the total trajectory is given by:
hence, the mean velocity is 8.4 m/s