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amid [387]
2 years ago
12

Which food must be cooked at to at least 145 f 63c cheese fries baked potatoes steamed broccoli for a buffet table scrambled egg

s for a cause
Physics
1 answer:
pantera1 [17]2 years ago
6 0

The dish that has to be cooked to at least 145°f is scrambled eggs. Option C is correct.

<h3>What is temperature?</h3>

Temperature directs to the hotness or coldness of a body. It is denoted by T.Measured mainly in the °C.

For good food safety beef, pig and eggs must be cooked at a temperature of 145°f. A minimum of 15 seconds must pass with the temperature held steady.

The temperature range in which the majority of bacteria thrive and multiply quickly is known as the temperature danger zone.

To keep away the eggs from the bacteria they must be cooked to at least 145°f. Scrambled eggs are the food that must be cooked to at least 145°f.

Hence, option C is correct.

To learn more about the temperature refer to the link;

brainly.com/question/7510619

#SPJ1

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16. Two capacitors have an equivalent
Gennadij [26K]

Answer:

C1 + C2 = 30     parallel connection

C1 * C2 / (C1 + C2) = 7.2  series connection

C1 * C2 = 7.2 * (C1 + C2) = 216

C2 + 216 / C2 = 30    using first equation

C2^2 + 216 = 30 C2

C2^2 - 30 C2 + 216 = 0

C2 = 12 or 18    solving the quadratic

Then C1 = 18 or 12

5 0
3 years ago
A 40 kg person sits on top of a 400 kg rock. What is the person’s weight? 390 N
algol13

The weight of the person is given by:

W = mg

W = weight, m = mass, g = gravitational acceleration

Given values:

m = 40kg, g = 9.81m/s²

Plug in and solve for W:

W = 40(9.81)

W = 390N

7 0
3 years ago
A proposed ocean thermal-energy conversion (OTEC) system is a heat engine that would operate between warm water (16°C) at the oc
LenaWriter [7]

Answer:

3.46 %

Explanation:

We have given cooler temperature that is T_c = 6°C =273+6=279 K

And the warm temperature of water that is T_h=16^{\circ}C=16+273=289\ K

The maximum possible efficiency is given by \eta =1-\frac{T_c}{T_h}

So maximum efficiency \eta =1-\frac{T_c}{T_h}=1-\frac{279}{289}=0.0346=3.46 %

6 0
3 years ago
Two vehicles approach a right angle intersection and then suddenly collide. After the collision, they become entangled. If their
geniusboy [140]

Answer:

a. 11 m/s at 76° with respect to the original direction of the lighter car.

Explanation:

In this exercise, since both cars make a right angle, let's assume that the lighter car only has a horizontal velocity component (vx) and that the heavier one only has a vertical velocity component (vy). The final velocities for both components for the system can be determined as:

m_{1} v_{x1}+m_{2}v_{x2}=(m_{1}+m_{2})v_{fx}\\m_{1} v_{y1}+m_{2}v_{y2} =(m_{1}+m_{2})v_{fy}

Assume that the lighter car has a 1kg mass and that the heavier car has a 4 kg mass.

1*13 + 4*0 = (1+4) v_{fx}\\v_{fx}=\frac{13}{5} =2.6\\1*0 + 4*13 = (1+4) v_{fy}\\v_{fy}=\frac{13*4}{5} =10.4\\

The magnitude of the final velocity of the wreck can be found as:

v_{f}^{2}= v_{fx}^{2}+ v_{fy}^{2}\\v_{f}=\sqrt[]{2.6^{2} + 10.4^{2}} \\v_{f}= 10.72

The final velocity has an intensity of roughly 11 m/s

As for the angle, it can be determined in respect to the lighter car (x axis) as follows:

\theta = cos^{-1}(\frac{v_{fx} }{v_{f}} )\\\theta = cos^{-1}(\frac{2.6}{10.7} )\\\theta = 76^{o}

Therefore, the wreck has a velocity with an intensity of 11 m/s at 76° with respect to the original direction of the lighter car.

5 0
3 years ago
How have earthquake data been used to explore the size of convection currents in the mantle?
nadezda [96]
 <span>Vibration waves from earth quakes travel through the earth and have measurable speed. And the different temperatures and fluidity of the various regions of the mantle will change that speed and or reflect the vibration waves in different directions. With multiple vibration sensors around the world the time that it takes for vibrations to travel from one part of the world to another will tell you what is inside.</span>
8 0
3 years ago
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