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amid [387]
2 years ago
12

Which food must be cooked at to at least 145 f 63c cheese fries baked potatoes steamed broccoli for a buffet table scrambled egg

s for a cause
Physics
1 answer:
pantera1 [17]2 years ago
6 0

The dish that has to be cooked to at least 145°f is scrambled eggs. Option C is correct.

<h3>What is temperature?</h3>

Temperature directs to the hotness or coldness of a body. It is denoted by T.Measured mainly in the °C.

For good food safety beef, pig and eggs must be cooked at a temperature of 145°f. A minimum of 15 seconds must pass with the temperature held steady.

The temperature range in which the majority of bacteria thrive and multiply quickly is known as the temperature danger zone.

To keep away the eggs from the bacteria they must be cooked to at least 145°f. Scrambled eggs are the food that must be cooked to at least 145°f.

Hence, option C is correct.

To learn more about the temperature refer to the link;

brainly.com/question/7510619

#SPJ1

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IgorLugansk [536]

(a) 273.9 V

The power rating of the resistor is given by

P=\frac{V^2}{R}

where

P is the power rating

V is the potential difference across the resistor

R is the resistance

If the maximum power rating is P=5.0 W, and the resistance of the resistor is R=15 k\Omega = 15000 \Omega, then we can find the maximum potential difference across the resistor by re-arranging the previous equation for V:

V=\sqrt{PR}=\sqrt{(5.0 W)(15000 \Omega)}=273.9 V

(b) 1.6 W

In this case, we have:

R=9.0 k\Omega = 9000 \Omega is the resistance of the resistor

V=120 V is the potential difference across the resistor

So we can find the power rating by using the same formula of part (a):

P=\frac{V^2}{R}=\frac{(120 V)^2}{9000 \Omega}=1.6 W

(c) Maximum voltage: 14.1 V; Rate of heat: 2.00 W and 3.00 W

Here we have two resistors of

R_1 = 100 \Omega\\R_2 = 150 \Omega

and each resistor has a power rating of

P = 2.00 W

So the greatest potential difference allowed in the first resistor is

V=\sqrt{PR_1}=\sqrt{(2.00 W)(100 \Omega)}=14.1 V

While the greatest potential difference allowed in the second resistor is

V=\sqrt{PR_2}=\sqrt{(2.00 W)(150 \Omega)}=17.3 V

So the greatest potential difference allowed not to overheat either of the resistor is 14.1 V.

In this condition, the power dissipated on the first resistor is 2.00 W, while the power dissipated on the second resistor is

P_2 = \frac{V^2}{R_2}=\frac{(14.1 V)^2}{150 \Omega}=1.33 W

And this corresponds to the rate of heat generated in the first resistor (2.00 W) and in the second resistor (1.33 W).

4 0
3 years ago
12. The bond formed when two atoms share a pair of electrons is called a
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Explanation:

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3 years ago
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ser-zykov [4K]

D. a concave mirror

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3 years ago
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Mike is standing on the roof of a building looking at the roof of the neighboring building that is 15 meters away and 10 meters
amid [387]

Answer:

Part a)

t = 1.65 s

Part b)

x = 40.4 m

Since the distance of other building is 15 m so YES it can make it to other building

Part c)

v = 27.3 m/s

direction of velocity is given as

[tex]\theta = 26.35 degree

Explanation:

Part a)

acceleration due to gravity on this planet is 3/4 times the gravity on earth

So the acceleration due to gravity on this new planet is given as

a = \frac{3}{4}(9.81)

a = 7.36 m/s^2

now the vertical displacement covered by the canister is given as

y = 10 m

now by kinematics we have

y = \frac{1}{2}gt^2

10 = \frac{1}{2}(7.36)t^2

t = 1.65 s

Part b)

Horizontal speed of the canister is given as

v_x = 24.5 m/s

now the distance moved by it

x = v_x t

x = 24.5 (1.65)

x = 40.4 m

Since the distance of other building is 15 m so YES it can make it to other building

Part c)

Final velocity in X direction will remains the same

v_x = 24.5 m/s

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v_y = v_i + at

v_y = 0 + (7.36)(1.65)

v_y = 12.14 m/s

now magnitude of velocity is given as

v = \sqrt{v_x^2 + v_y^2}

v = \sqrt{24.5^2 + 12.14^2}

v = 27.3 m/s

direction of velocity is given as

\theta = tan^{-1}\frac{v_y}{v_x}

\theta = tan^{-1}\frac{12.14}{24.5}

[tex]\theta = 26.35 degree

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