1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
amid [387]
2 years ago
12

Which food must be cooked at to at least 145 f 63c cheese fries baked potatoes steamed broccoli for a buffet table scrambled egg

s for a cause
Physics
1 answer:
pantera1 [17]2 years ago
6 0

The dish that has to be cooked to at least 145°f is scrambled eggs. Option C is correct.

<h3>What is temperature?</h3>

Temperature directs to the hotness or coldness of a body. It is denoted by T.Measured mainly in the °C.

For good food safety beef, pig and eggs must be cooked at a temperature of 145°f. A minimum of 15 seconds must pass with the temperature held steady.

The temperature range in which the majority of bacteria thrive and multiply quickly is known as the temperature danger zone.

To keep away the eggs from the bacteria they must be cooked to at least 145°f. Scrambled eggs are the food that must be cooked to at least 145°f.

Hence, option C is correct.

To learn more about the temperature refer to the link;

brainly.com/question/7510619

#SPJ1

You might be interested in
A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 79.6 m/s at ground level.
Dimas [21]

Answer:

The rocket is motion above the ground for 44.7 s.

Explanation:

The equations for the height of the rocket are as follows:

y = y0 + v0 · t + 1/2 · a · t²

and, after the engine fails:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the rocket at time t

y0 =  initial height

v0 = initial speed

t=  time

a = acceleration due to the engines

g = acceleration due to gravity

First, let´s calculate the time the rocket is being accelerated by the engines:

(The center of the framer of reference is located at the ground, y0 = 0).

y = y0 + v0 · t + 1/2 · a · t²

1190 m = 0 m + 79.6 m/s · t + 1/2 · 4.10 m/s² · t²

0 = 2.05  m/s² · t² + 79.6 m/s · t - 1190 m

Solving the quadratic equation:

t = 11.5 s  (the other value of t is discarded because it is negative).

At that time, the engines fail and the rocket starts to fall. The equation of the height will be:

y = y0 + v0 · t + 1/2 · g · t²

The initial velocity (v0) will be the velocity acquired during 11.5 s of acceleration plus the initial velocity of launch:

v = v0 + a · t

v = 79.6 m/s + 4.10 m/s² · 11.5 s

v = 126.8 m/s

Now, we can calculate the time it takes the rocket to reach the ground (y = 0) from a height of 1190 m:

y = y0 + v0 · t + 1/2 · g · t²

0 m = 1190 m + 126.8 m/s · t - 1/2 · 9.80 m/s² · t²

Solving the quadratic equation:

t = 33.2 s

Then, the total time the rocket is in motion is (33.2 s + 11.5 s) 44.7 s

 

5 0
4 years ago
An airplane is flying horizontally with a constant momentum during a time interval ?t. (a) Is there a net impulse acting on the
goldenfox [79]

Answer:

Explanation:

Given

Airplane is flying with horizontally with a constant momentum during time interval \Delta t

Impulse is given by change in momentum, so there is no net impulse on the Plane because momentum is constant

(b) As there is no change in momentum therefore impulse of thrust and air drag is balanced i.e. both are equal in magnitude but act in opposite direction                            

7 0
3 years ago
An object moves with a constant speed of 20 m/s on a circular track of radius 100 m. What is the tangential acceleration of the
MissTica

Answer:4s^-1

Explanation:Tangential Acceleration=v^2/r=(20)²/100=400/100

4 0
3 years ago
In an experiment, an object is released from rest from the top of a building. Its speed is measured as it reaches a point that i
NikAS [45]

Answer:

so the speed will increase by 1.44 times then the initial speed if the distance is increased to double

Explanation:

As we know that the air friction or resistance due to air is neglected then we can use the equation of kinematics here

v_f^2 - v_i^2 = 2 a d

since we released it from rest so we have

v_i = 0

so here we have

v_f = \sqrt{2gd}

now if the distance is double then we have

v_f' = \sqrt{2g(2d)}

now from above two equations we can say that

v_f' = \sqrt2 v_f

so the speed will increase by 1.44 times then the initial speed if the distance is increased to double

4 0
3 years ago
How many degrees equal π in radians? How many revolutions (turns) equal π radians? ​
kodGreya [7K]

Answer:

It follows that the magnitude in radians of one complete revolution (360 degrees) is the length of the entire circumference divided by the radius, or 2πr / r, or 2π. Thus 2π radians is equal to 360 degrees, meaning that one radian is equal to 180/π ≈ 57.295779513082320876 degrees.

Explanation:

6 0
3 years ago
Other questions:
  • A satellite circles the moon at a distance above its surface equal to 2 times the radius of the moon. The acceleration due to gr
    5·2 answers
  • What are some things that can happen to an object when a forces acts on it?
    15·2 answers
  • The tip of a pinwheel is 0.24 m from the center. The pinwheel spins 5 times each second. What is the tangential speed of the tip
    5·2 answers
  • A box sliding on a horizontal frictionless surface encounters a spring attached to a rigid wall and compresses the spring by a c
    9·1 answer
  • Difference Between Photometry and Spectrophotometry ?<br><br>​
    5·1 answer
  • A ball is thro.d hit the grouvelocity)?
    13·1 answer
  • A block moves along a table at a constant velocity and then rolls off the edge of the table. The forces that should be included
    7·1 answer
  • Why does oil not dissolve in water?
    11·1 answer
  • If this charged soot particle is now isolated (that is, removed from the electric field described in the previous part), what wi
    5·1 answer
  • Points a and b are nearby a proton in otherwise empty space. the potential is chosen to be zero very far away from the proton. t
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!