Question

4. A big league hitter attacks a fastball! The ball has a mass of 0.16 kg. It is pitched at 38 m/s. After the player hits the ball, it is now traveling 44 m/s in the opposite direction. The impact lasted 0.002 seconds. How big of a force did the ballplayer put on that ball?

Answer 1

The change in momentum of the ball is
0.16 (44 - 38) = 0.96 kg m/s
And this should equate to the impulse delivered by a hitting force
F t = 0.96
F (0.002) = 0.96
F = 480 N<span />