From Q = mcΔΤ, the specific heat capacity, c, of the metal that was cooled is c = Q/mΔT = (-769 J)/(46.4 g)(30.0 °C - 101.0 °C) = 0.233 J/g °C. From the table, it appears that this is the specific heat capacity of silver. So, the metal is most like silver.
Note: The value for Q was written as a negative value in the equation as heat energy was given off by the metal when the metal was cooled (from the metal’s point of view, it’s losing heat energy).
What your question for number 3
Answer:
The answer would either be Carbon or Silicon.
Explanation:
Answer:
5
Explanation:
all you do is the math expression