Answer:
-5%
Explanation:
We know that volume is mass/density
So to find percentage
Let first mass be = M1
Second be 0.94m( 1-6%)
Second density be=0.99
First density be d
So finlq volume v2= 0.94m/0.99p=
V2= (0.94/0.99)V1
V2= 0.95v1
So volume decrease will be 1-0.95= 0.05
= -5%
Answer:
3m/s
Explanation:
K.E= (1/2)mv^2
216j= (1/2)48kg • v^2
216J=24kg•v^2
v^2 = (216J)/(24kg)
v^2= 9m^2/s^2
/sqrt{v^2} = /sqrt{9m^2/s^2}
V =3m/s
It will experience centripetal accelaration.
Answer:
e). 
Explanation:
As we know that wheel is turned by 90 degree angle
so the angular speed of the wheel is given as
now we have
now the centripetal acceleration of the point P is given as
tangential acceleration is given as
now net acceleration is given as
Answer:
1. increases
2. increases
3. increases
Explanation:
Part 1:
First of all, since the box remains at rest, the horizontal net force acting on the box must equal zero:
F1 - fs = 0.
And this friction force fs is:
fs = Nμs,
where μs is the static coefficient of friction, and N is the normal force.
Originally, the normal force N is equal to mg, where m is the mass of the box, and g is the constant of gravity. Now, there is an additional force F2 acting downward on the box, which means it increases the normal force, since the normal force by Newton's third law, is the force due to the surface acting on the box upward:
N = mg + F2.
So, F2 is increasing, that means fs is increasing too.
Part 2:
As explained in the part 1, N = mg + F2. F2 is increasing, so the normal force is thus increasing.
Part 3:
In part 1 and part 2, we know that fs = Nμs, and since the normal force N is increasing, the maximum possible static friction force fs, max is also increasing.
