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kvasek [131]
3 years ago
12

A 65 N boy sits on a sled weighing 52 N on a horizontal surface. The coefficient of friction between the sled and the snow is 0.

012. What is the magnitude of the frictional force?
Physics
1 answer:
pogonyaev3 years ago
3 0

Answer:

1.40 N

Explanation:

The magnitude of the frictional force is given by:

F=\mu N

where

\mu is the coefficient of friction

N is the magnitude of the normal reaction

The coefficient of friction for this problem is \mu=0.012. The magnitude of the normal reaction is equal to the combined weight of the boy and the sled, because the surface is horizontal, so

N=65 N+52 N=117 N

Therefore, the frictional force is

F=\mu N=(0.012)(117 N)=1.40 N

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A wire loop of radius 0.50 m lies so that an external magnetic field of magnitude 0.40 T is perpendicular to the loop. The field
vazorg [7]

The magnitude of the induced emf is given by:

ℰ = |Δφ/Δt|

ℰ = emf, Δφ = change in magnetic flux, Δt = elapsed time

The magnetic field is perpendicular to the loop, so the magnetic flux φ is given by:

φ = BA

B = magnetic field strength, A = loop area

The area of the loop A is given by:

A = πr²

r = loop radius

Make a substitution:

φ = B2πr²

Since the strength of the magnetic field is changing while the radius of the loop isn't changing, the change in magnetic flux Δφ is given by:

Δφ = ΔB2πr²

ΔB = change in magnetic field strength

Make another substitution:

ℰ = |ΔB2πr²/Δt|

Given values:

ΔB = 0.20T - 0.40T = -0.20T, r = 0.50m, Δt = 2.5s

Plug in and solve for ℰ:

ℰ = |(-0.20)(2π)(0.50)²/2.5|

ℰ = 0.13V

3 0
3 years ago
A 0.150 kg baseball has 118 j of KE. how fast is the ball moving?(unit=m/s)
MrRissso [65]

Answer:

Explanation 118 = (1/2) * 0.15 * v² 118 = 0.075 * v² v² = 1573.33 m/s ... since KE = m/2*V^2 , then : V = √2KE/m = √20*118/1.5 = 39.67 m//sec ( 142.8 km/h ; 88.75 mph).:

4 0
4 years ago
A particle accelerator fires a proton into a region with a magnetic field that points in the +x-direction (a) If the proton is m
pochemuha

Answer:

a) -z direction, b) +z direction, c) F=0  

Explanation:

The magnetic force is given by the expression

        F = q v x B

the bold indicate vectors, this equation can be separated in its module

        F = a v B sin θ

and where θ is the angles between the speed and the magnetic field.

The direction of the force can be found with the right-hand rule. For a positive charge, the thumb goes in the direction of speed, the fingers extended in the direction of the magnetic field and the palm points in the direction of the force, if the charge is negative the force is in the opposite direction.

a) Let's apply this to our case

the proton is positively charged

moves in the direction of + x

The magnetized field goes in the direction of y

therefore applying the right hand rule the force must be in the direction of the negative part of the z-axis (-z)

The right-hand rule is used to find this address.

b)  in this case it indicates that the proton moves in the recode of -y

again we apply the right hand rule and the force is in the direction of + z

c)   The proton moves in the x direction

In this case the force is zero because the angle between the field and the speed is zero and the sine is zero, therefore the force is zero

4 0
4 years ago
A car has a mass of 1,000 kilograms. The weight of the car is blank newtons. Use g = 9.8 N/kg for gravity.
Komok [63]
The weight of an object is mass*acceleration. In this case mass*g.
1000*9.8=9800
So the car has a weight of 9800 N.
3 0
3 years ago
A boy is pulling a 150 kg crate with a force of 1150 N. If the crate experiences a frictional force of 490 N, find:
valentina_108 [34]
<h3><u>For the aceleration:</u></h3>

First, let's find the resultant, and <u>applicate 2nd law of Newton</u> using the resultant, so:

R = ma

F - Ff = ma

Data:

F = Force = 1150 N

Ff = Friction force = 490 N

m = Mass = 150 kg

a = Aceleraction = ?

Replacing according our data:

1150 N - 490 N = 150 kg * a

660 N = 150 kg * a

660 N / 150 kg = a

a = 4,4 m/s²   ← Aceleration of the object

<h3><u>For the normal force:</u></h3>

The normal force IS NOT the resultant force, the normal force's the force between the ground and the object, in another words, is the weight of the object, and for the weight:

w = mg

w = 150 kg * 10 m/s²

w = 1500 N   ← Normal force between object and ground.

7 0
3 years ago
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