Question

A 65 N boy sits on a sled weighing 52 N on a horizontal surface. The coefficient of friction between the sled and the snow is 0.012. What is the magnitude of the frictional force?

Answer 1

Answer:

1.40 N

Explanation:

The magnitude of the frictional force is given by:

$F=\mu N$

where

$\mu$ is the coefficient of friction

N is the magnitude of the normal reaction

The coefficient of friction for this problem is $\mu=0.012$. The magnitude of the normal reaction is equal to the combined weight of the boy and the sled, because the surface is horizontal, so

$N=65 N+52 N=117 N$

Therefore, the frictional force is

$F=\mu N=(0.012)(117 N)=1.40 N$