1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andrey2020 [161]
3 years ago
11

When the skater starts 7 mm above the ground, how does the speed of the skater at the bottom of the track compare to the speed o

f the skater at the bottom when the skater starts 4 mm above the ground?
Physics
1 answer:
Eva8 [605]3 years ago
8 0

Answer:

Speed is higher and 1.32 times greater.

Explanation:

Considering downward motion as positive.

Given:

Case 1:

Initial height (h₁) = 7 mm = 0.007 m [1 mm =0.001 m]

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u₁) = 0 m/s

Final velocity (v₁) = ?

Using conservation of energy, we have:

Decrease in potential energy = Increase in Kinetic energy

mgh_1=\frac{1}{2}mv_1^2\\\\v_1=\sqrt{2gh_1}=\sqrt{2\times 9.8\times 0.007}=0.37\ m/s

Case 2:

Initial height (h₂) = 4 mm = 0.004 m

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u₂) = 0 m/s

Final velocity (v₂) = ?

Using conservation of energy, we have:

Decrease in potential energy = Increase in Kinetic energy

mgh_2=\frac{1}{2}mv_2^2\\\\v_2=\sqrt{2gh_2}=\sqrt{2\times 9.8\times 0.004}=0.28\ m/s

From the above values, we can conclude:

v_1>v_2

Also,

\frac{v_1}{v_2}=\frac{0.37}{0.28}=1.32\\\\v_1=1.32v_2

So, the velocity in the first case is 1.32 times greater than velocity in second case.

You might be interested in
The half-life of iodine-131 is 8 days. Chan Hee examines two samples of iodine-131. Sample 1: 10 g Sample 2: 20 g What can Chan
Illusion [34]
Chan Hee can expect to observe about the samples after 16 days is that three-fourths of each sample will have undergone radioactive decay. The best answer is letter B.
4 0
3 years ago
Why are there only two elements in the first period of the periodic table?(1 point)
tester [92]

Answer:

because each row increases in atomic mass by a specific number, so anything over five is in the second row.

8 0
2 years ago
The force diagram represents a girl pulling a sled with a mass of 6.0 kg to the left with a force of 10.0 N at a 30.0 degree ang
Vilka [71]
Normal Force = 54 N
acceleration = 1.2 m/s^2

For Normal Force:
According to the force diagram, we can come up with the equation (all up and down forces):

10 sin 30 + Normal Force - 58.8 = 0
Normal Force = 53.8 N = 54 N

For acceleration:
According to the force diagram, we can come up with the equation (all left and right forces):

10 cos 30 - 1.5 = (6.0) (Acceleration)
Acceleration = 1.19 m/s^2 = 1.2 m/s^2 
3 0
3 years ago
Read 2 more answers
Describe the pattern of air circulation between an area of low pressure and high pressure
lakkis [162]
The sinking of cold air creates regions of high pressure and this air travels to lower pressure regions produced by the rising motion of warm air. This process results in air circulation.
4 0
3 years ago
what is the energy (in j) of a photon required to excite an electron from n = 2 to n = 8 in a he⁺ ion? submit an answer to three
grin007 [14]

Answer:

Approximately 5.11 \times 10^{-19}\; {\rm J}.

Explanation:

Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.

Look up the Rydberg constant for hydrogen: R_{\text{H}} \approx 1.0968\times 10^{7}\; {\rm m^{-1}.

Look up the speed of light in vacuum: c \approx 2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}.

Look up Planck's constant: h \approx 6.6261 \times 10^{-34}\; {\rm J \cdot s}.

Apply the Rydberg formula to find the wavelength \lambda (in vacuum) of the photon in question:

\begin{aligned}\frac{1}{\lambda} &= R_{\text{H}} \, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\end{aligned}.

The frequency of that photon would be:

\begin{aligned}f &= \frac{c}{\lambda}\end{aligned}.

Combine this expression with the Rydberg formula to find the frequency of this photon:

\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}.

Apply the Einstein-Planck equation to find the energy of this photon:

\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}.

(Rounded to three significant figures.)

6 0
2 years ago
Other questions:
  • Which of the following is an example of a noninfectious disease?
    13·2 answers
  • Explain why streets and highways have speed limits and not velocity limits.
    6·1 answer
  • an object traveling 200 feet per second slows to 50 feet per second in 5 seconds. Calculate the acceleration of the object
    15·1 answer
  • When a beam of light passes at an oblique angle into a material of lower optical density, the angle of incidence is
    13·2 answers
  • What are the products in the reaction in the introduction above? Select all that apply.
    8·1 answer
  • Give two examples of gravity in the solar system
    11·1 answer
  • Use the information from the graph to answer the
    10·1 answer
  • A certain wave has a wavelength of 35 meters and a frequency of 4.0 Hz. What is the speed of the wave?
    10·2 answers
  • Pls give motivation, a paragraph pls! I'll give brainliest to whoever's is the biggest and best! I'll give 50 points, it is for
    13·1 answer
  • Information travels at 120 metres per second in neurones. Calculate the time it would take for the information to travel 2.3 m a
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!