Answer:
The pair will be:
- NH3/NH4⁺
- ClO⁻/HClO
Explanation:
A conjugate acid is formed after a base has reacted/accepted a proton.
Since H2O is amphiprotic, we can use it as the acid.
NH3 + H2O ⇄ NH4⁺ + OH⁻
ClO⁻ + H2O ⇄ HClO + OH⁻
after reacting, the base form conjugate acid.
Mass of vaporized triethylamine : 2.606 g
<h3>Further explanation</h3>
Given
0.5 L triethylamine
P = 18.5 psi
T = 25 °C
Required
mass of vaporized triethylamine
Solution
Conversion :
P 18.5 psi = 1,26 atm
T = 25 +273 = 298 K
Ideal gas law :
PV=nRT
n = PV/RT
Input the value :
n = (1.26 atm x 0.5 L) /(0.08205 x 298)
n = 0.0258
MW triethylamine = 101 g/mol
Mass triethylamine :
= n x MW
= 0.0258 x 101 g/mol
= 2.606 g
P = nRT/V
P = 3.5 x 10^-3 x 0.082 x 298 /0.5
P = 0.171 m Hg
P = 171 mm Hg
hope this helps
Answer:
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Explanation:
Answer:
2.8g/cm³
Explanation:
Given parameters:
Mass of cube = 42g
Volume of cube = 15cm³
Unknown:
Density of the cube = ?
Solution:
Density is defined as the mass per unit volume of a substance. It is mathematically expressed as:
Density =
So;
Density =
= 2.8g/cm³