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Zanzabum
3 years ago
11

Water is produced from the reaction of hydrogen and oxygen gas, according to the equation below. What is the excess reactant in

the reaction of 4.2 moles of hydrogen with 3.0 moles of oxygen?
2H2(g) + O2(g) = 2H2O(l)
Select one:
a.Water
b.Oxygen
c.No excess reactant
d.Hydrogen
Chemistry
2 answers:
insens350 [35]3 years ago
7 0

Answer:

2H2O means two molecules of water(H2O)

VashaNatasha [74]3 years ago
5 0

Answer:

b.Oxygen

this is the excess reactant

Why?

2 moles of hydrogen react with 1 mole of oxygen. So, 4.2 moles of hydrogen would need 2.1 moles of oxygen. There are 3.0 moles of oxygen. So, there are 0.9 moles of oxygen in excess.

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Which change will cause the greatest increase in the rate of reaction for this chemical reaction? 8Zn(s) + S8(s) 8ZnS(s) A. addi
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2 years ago
Calculate the ph of the solution resulting by mixing 20.0 ml of 0.15 m hcl with 20.0 ml of 0.10 m koh
Aliun [14]

Answer:

1.60.

Explanation:

  • The no. of millimoles of HCl = MV = (0.15 M)(20.0 mL) = 3.0 mmol.
  • The no. of millimoles of KOH = MV = (0.10 M)(20.0 mL) = 2.0 mmol.

<em>Since the no. of millimoles of HCl is larger than that of KOH. The solution is acidic.</em>

<em></em>

∴ M of remaining HCl [H⁺] remaining = (NV)HCl - (NV)KOH/V total = (3.0 mmol) - (2.0 mmol) / (40.0 mL) = 0.025 M.

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5 0
3 years ago
A 4.36-g sample of an unknown alkali metal hydroxide is dissolved in 100.0 mL of water. An acid-base indicator is added, and the
BARSIC [14]

Answer:

Rb+

Explanation:

Since they are telling us that the equivalence point was reached after 17.0 mL of   2.5 M HCl were added , we can calculate the number of moles of HCl which neutralized our unknown hydroxide.

Now all the choices for the metal cation are monovalent, therefore the general formula for our unknown is XOH and  we know the reaction is 1 equivalent acid to 1 equivalent base. Thus we have the number of moles, n,  of XOH and from the relation n = M/MW we can calculate the molecular weight of XOH.

Thus our calculations are:

V = 17.0 mL x 1 L / 1000 mL = 0.017 L

2.5 M HCl x 0.017 L = 2.5 mol/ L x 0.017 L = 0.0425 mol

0.0425 mol = 4.36 g/ MW XOH

MW of XOH = (atomic weight of X + 16 + 1)

so solving the above equation we get:

0.0425 = 4.36 / (X + 17 )

0.7225 +0.0425X = 4.36

0.0425X = 4.36 -0.7225 = 3.6375

X = 3.6375/0.0425 = 85.59

The unknown alkali is Rb which has an atomic weight of 85.47 g/mol

6 0
3 years ago
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