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2 years ago

A student redid the experiment of mixing room temperature water and warm

Physics

2 answers:

Ulleksa [173]2 years ago

8 0

Answer:

The answer is B

Explanation:

Len [333]2 years ago

7 0

Answer:

I think B or C it won't lower so I'll go with B bc warm water is hotter than regular temp water

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A wooden artifact from a Chinese temple has a 14C activity of 41.0 counts per minute as compared with an activity of 58.2 counts

prohojiy [21]

Answer:

Explanation:

The relation between activity and number of radioactive atom in the sample is as follows

dN / dt = λ N where λ is disintegration constant and N is number of radioactive atoms

For the beginning period

dN₀ / dt = λ N₀

58.2 = λ N₀

similarly

41 = λ N

dividing

58.2 / 41 = N₀ / N

N = N₀ x .70446

formula of radioactive decay

$N=N_0e^{-\lambda t }$

$.70446 =e^{-\lambda t }$

- λ t = ln .70446 = - .35

t = .35 / λ

λ = .693 / half life

= .693 / 5715

= .00012126

t = .35 / .00012126

= 2886.36

= 2900 years ( rounding it in two significant figures )

7 0

3 years ago

A car tire rotates with an average angular speed of 32 rad/s. In what time interval will the tire rotate 3.5 times? Answer in un

stiks02 [169]

Answer:

$\Delta t = 0.687\ s$

Explanation:

given,

Angular speed of the tire = 32 rad/s

Displacement of the wheel = 3.5 rev

Δ θ = 3.5 x 2 π

= 7 π rad

now,

Time interval of the car to rotate 7π rad

using equation

$\omega_{avg} =\dfrac{\Delta \theta}{\Delta t}$

$\Delta t=\dfrac{7\pi}{32}$

$\Delta t = 0.687\ s$

Time taken to rotate 3.5 times is equal to 0.687 s.

3 0

3 years ago

An athlete runs 40 meters north and 30 meters south

Serggg [28]

Answer:

only ten meters north from starting point

Explanation:

7 0

3 years ago

A ball thrown straight upwards with an initial velocity of 15 m/s. Calculate how long the ball will remain in the air and the ma

GenaCL600 [577]

Answer:

The ball remain in air for 3.06 seconds.

Maximum height reached = 22.94 m

Explanation:

We have equation of motion v = u + at

At maximum height, final velocity, v =0 m/s

Initial velocity = 15 m/s

acceleration = -9.81 m/s²

Substituting

0 = 15 -9.81 t

t = 1.53 s

Time of flight = 2 x 1.53 = 3.06 s

The ball remain in air for 3.06 seconds.

We also have equation of motion v² = u² + 2as

At maximum height, final velocity, v =0 m/s

Initial velocity = 15 m/s

acceleration = -9.81 m/s²

Substituting

0² = 15² - 2 x 9.81 x s

s = 22.94 m

Maximum height reached = 22.94 m

3 0

3 years ago

Why do stars have names

zmey [24]

Astronomers give stars names so that they're able to identify and keep track of them more easily.

7 0

3 years ago