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Doss [256]
4 years ago
10

Directions: Answer the following questions in complete sentences. a. Describe four properties of acids that you learned in this

lesson. b. Describe four of the properties of bases that you learned in this lesson. c. What are the products produced when an acid and base react together? d. Now it is time to do a scavenger hunt around your house to find more examples of acids and bases. Be sure to check in your fridge, medicine cabinet, and in the cleaning supplies. e. Don’t forget to read the labels on products to find the names or formulas of acids and bases they may contain. f. Find at least five acids and five bases for your list, making sure that there are some items on your list that were not mentioned in the lesson. Whenever possible, list the product/item and the formula or name of the acid or base.
Chemistry
1 answer:
sladkih [1.3K]4 years ago
7 0

Answer:

  • see below

Explanation:

<em><u> a. Describe four properties of acids that you learned in this lesson. </u></em>

<u>1. Acids taste sour</u>

  • For instance, taste some lemon juice

<u>2. Acids are corrosive</u>

  • Acids in contact with organic tissue or metals attack and, eventually, can destroy them. For instance chloric adis and sulfuric acid. Acids burn the skin.

<u>3. Acids react with metals releasing hydrogen gas</u>

  • For instance:

                            2HCl(aq)+2Na(s)\rightarrow 2NaCl(aq)+H_2(g)\uparrow

<u>4. The pH of acids is below 7.</u>

  • pH is the negative logarithm of the hydrodium concentration. HIgh concentrations of hydronum yield low pH: For instance:

                          [H_3O]=2.0M \impliespH=-log\dfrac{1}{[H_3O^+]}=-log\dfrac{1}{2}=0.3

<u>5. Acids conduct electricity:</u>

  • Acids ionize in water, producing hydronium ions. The ions carry charge. The motion or flow of charge is electric current.

<u><em>b. Describe four of the properties of bases that you learned in this lesson. </em></u>

<u>1. Bases taste bitter</u>

  • For instance, taste some soap

<u>2. Bases are caustic and corrosive</u>

  • Bases also damage organic tissue and attack metals. Thus they are corrosive such as acids. But strong bases are also named caustic. They cause damage similar to burns but in a different way.

<u>3. The pH of bases is above 7.</u>

  • pOH is the negative logarithm of OH⁻ ion. And pH + pOH = 14

         [OH^-]=1.0\impliespOH=-log(1/1.0)=-log(0.1)=1\\ \\ pH=14-pOH\\\\pH=13

<u>4. Bases conduct electricty.</u>

  • Bases ionize in water releasing OH⁻ which carry charge, the flow of charge is current.

c. What are the products produced when an acid and base react together?

Acids and bases react together neutralizing each other, producing salt and water.

For instance:

           HCl+NaOH\rightarrow NaCl(salt)+H_2O(water)\\\\\\HNO_3+NaOH\rightarrow NaNO_3(salt)+H_2O(water)

<u><em>d. Examples of acids and bases. Be sure to check in your fridge, medicine cabinet, and in the cleaning supplies. </em></u>

From fridge (or the food pantry):

  • Tomato juice: acid
  • Lemon juice: acid
  • Orange juice: acid
  • soda beverages: acid
  • vinegard: acid

  • baking soda: base

From medicine cabinet:

  • aspirin: acid
  • ibuprofen: acid

Cleaning supplies:

  • muriatic acid: acid
  • soap: base
  • bleach: base
  • household ammonia: base
  • lye: base

<u><em>e. Names or formulas of acids and bases they may contain. </em></u>

  • Tomato juice, lemon juice, and orange juice contain citric acid: C₆H₈O₇

  • Baking soda is sodium bicarbonate: NaHCO₃

  • Vinegar is diluted acetic acid: CH₃COOH

  • Soda beverages: contain carbon dioxide CO₂, and some may contain phosphoric acid H₃PO₄

  • Muriatic acid is diluted hydrochloric acid: HCl

  • aspiring is actyilsalicylic acid: C₉H8O₄

  • ibufrofen is isobutylphenylpropionic acid.

  • soap: chemically they are fatty acids metal salts.

  • bleach is sodium hypochlorite: ClOH.

  • Lye is sodium hyroxide: NaOH

  • Hosehold ammonia: NH₄OH

<em><u>f. Find at least five acids and five bases for your list, making sure that there are some items on your list that were not mentioned in the lesson. Whenever possible, list the product/item and the formula or name of the acid or base. </u></em>

<u>Acids: </u>

  • citric acid: C₆H₈O₇
  • soda beverages: carbon dioxide, CO₂
  • vinegard: acetic acid: CH₃COOH
  • aspirin: acetylsalicylic acid
  • ibuprofen: isobutylphenylpropionic acid
  • muriatic acid: HCl

<u>Bases:</u>

  • baking soda: sodium bicarbonate: NaHCO₃
  • soap: fatty acid metal salts.
  • bleach: sodium hypochlorite: HClO
  • household ammonia: NH₄OH
  • lye: sodium hydroxide: NaOH
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a) ΔHºrxn = 116.3 kJ, ΔGºrxn = 82.8 kJ,  ΔSºrxn =  0.113 kJ/K

b) At 753.55 ºC or higher

c )ΔG =  1.8 x 10⁴ J

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Explanation:

a)                                 C6H5−CH2CH3  ⇒  C6H5−CH=CH2  + H₂

ΔHf kJ/mol                    -12.5                           103.8                      0

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Using Hess law to calculate  ΔHºrxn we have

ΔHºrxn  = ΔHfº C6H5−CH=CH2 +  ΔHfº H₂ - ΔHºfC6H5−CH2CH3

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ΔHºrxn = 116.3 kJ

Similarly,

ΔGrxn = ΔGºf C6H5−CH=CH2 +  ΔGºfH₂ - ΔGºfC6H5CH2CH3

ΔGºrxn=   202.5 kJ + 0 kJ - 119.7 kJ  = 82.8 kJ

ΔSºrxn = 238 J/mol + 130.6 J/mol -255 J/K = 113.6 J/K = 0.113 kJ/K

b) The temperature at which the reaction is spontaneous or feasible occurs when ΔG becomes negative and using

ΔGrxn =  ΔHrxn -TΔS

we see that will happen when the term  TΔS  becomes greater than ΔHrxn since ΔS  is positive  , and so to sollve for T we will make ΔGrxn equal to zero and solve for T. Notice here we will make the assumption that  ΔºHrxn and ΔSºrxn remain constant at the higher temperature  and will equal the values previously calculated for them. Although this assumption is not entirely correct, it can be used.

0 = 116 kJ -T (0.113 kJ/K)

T = 1026.5 K  =  (1026.55 - 273 ) ºC = 753.55 ºC

c) Again we will use

                       ΔGrxn =  ΔHrxn -TΔS

to calculate ΔGrxn   with the assumption that ΔHº and ΔSºremain constant.

ΔG =  116.3 kJ - (600+273 K) x 0.113 kJ/K =  116.3 kJ - 873 K x 0.113 kJ/K

ΔG =  116.3 kJ - 98.6 kJ =  17.65 kJ = 1.8 x 10⁴ J ( Note the kJ are converted to J to necessary for the next part of the problem )

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ΔG = -RTlnK and solve for K

- ΔG / RT = lnK  ∴ K = exp (- ΔG / RT)

K = exp ( - 1.8 x 10⁴ J /( 8.314 J/K  x 873 K)) = 8.2 x 10⁻²

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