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3 years ago

ILL Give you brainlist if you answer it’s really URGENT PLS

Mathematics

2 answers:

forsale [732]3 years ago

6 0

Answer:

A (3/2, 9/2)

Step-by-step explanation:

Let's take the first solution which is (3/2 , 9/2). If we substitute 3/2 into x we get the equation (3/2)^2 we get y as 9/4 not 9/2, therefore (3/2 , 9/2) does not lie on the curve y = x^2

Lyrx [107]3 years ago

6 0

Answer:

see below

Step-by-step explanation:

y = x^2

Substitute the points in and see if it is true

y = (3/2) ^2 = 9/4 not true

y = (-1) ^2 = 1 true

y = (4) ^2 = 16 true

y = (1/2) ^2 = 1/4 true

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Complete the identity. 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?

Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified

Given

$sec^4 x + sec^2 x tan^2 x - 2 tan^4 x$

Required

Simplify

$(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2$

Represent $sec^2x$ with a

Represent $tan^2x$ with b

The expression becomes

$a^2 + ab- 2 b^2$

Factorize

$a^2 + 2ab -ab- 2 b^2$

$a(a + 2b) -b(a+ 2 b)$

$(a -b) (a+ 2 b)$

Recall that

$a = sec^2x$

$b = tan^2x$

The expression $(a -b) (a+ 2 b)$ becomes

$(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

..............................................................................................................................

In trigonometry

$sec^2x =1 +tan^2x$

Subtract $tan^2x$ from both sides

$sec^2x - tan^2x =1 +tan^2x - tan^2x$

$sec^2x - tan^2x =1$

..............................................................................................................................

Substitute 1 for $sec^2x - tan^2x$ in $(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)$

$(1) (sec^2x+ 2 tan^2x)$

Open Bracket

$sec^2x+ 2 tan^2x$ ------------------This is an equivalence

$(secx)^2+ 2 (tanx)^2$

Solving further;

................................................................................................................................

In trigonometry

$secx = \frac{1}{cosx}$

$tanx = \frac{sinx}{cosx}$

Substitute the expressions for secx and tanx

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$(secx)^2+ 2 (tanx)^2$ becomes

$(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2$

Open bracket

$\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})$

$\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}$

Add Fraction

$\frac{1 + 2sin^2x}{cos^2x}$ ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

$sin^2x + cos^2x= 1$

Make $sin^2x$ the subject of formula

$sin^2x= 1 - cos^2x$

................................................................................................................................

Substitute the expressions for $1 - cos^2x$ for $sin^2x$

$\frac{1 + 2(1 - cos^2x)}{cos^2x}$

Open bracket

$\frac{1 + 2 - 2cos^2x}{cos^2x}$

$\frac{3 - 2cos^2x}{cos^2x}$ ---------------------- This is another equivalence

8 0

3 years ago

Pam works a 52 hours in a week. Considering that a normal work week is 40 hours and paid at $1470 per hour and overtime is paid

Bezzdna [24]

Step-by-step explanation:

they way it is written, she has one of the best paying jobs in the world : $1470 per hour ...

but I guess it is really $14.70 per hour, right ?

that is then her basic wage : $14.70 per hour for 40 hours = 14.7 × 40 = $588.

her overtime rate is then 14.7×1.25 (one time and a quarter) = 18.375 ≈ $18.38

and she gets that rate for all hours beyond the basic 40 hours, so, 52-40 = 12 hours.

12×18.38 = $220.56

or if you need it totally precise

12×18.375 = $220.50

in total, her gross wage for that week is then

588 + 220.56 = $808.56

or totally precise with unrounded hourly rates

588 + 220.5 = $808.50

which would create a mean hourly rate

808.56/52 = $15.54923077... per hour ≈ $15.55 per hour

808.5/52 = $15.54807692... per hour ≈ $15.55 per hour

many payroll systems do the rounding of the hourly rates and then calculate the total amount (as the first option here). some others keep the full decimal positions in the calculation and then only round the total (as the second option here).

so, it is the question what your teacher expects here. I cannot tell from the description.

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Dahasolnce [82]

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Answer:

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Step-by-step explanation:

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