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Gnesinka [82]
3 years ago
14

What element has the electrons configuration of [Ar]4s^2 3d^5

Chemistry
1 answer:
Scilla [17]3 years ago
5 0

Answer:

Manganese

Explanation:

Using rules you will find the location on 3d^5 because you subtract one level when in the d block

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A sample of a compound made entirely from copper and oxygen was found to have a total mass of 0.143 g the mass of copper in the
tensa zangetsu [6.8K]

Mass of Oxygen: 0.0159 grams

Moles of Oxygen: 9.94x10^-4

To find the mass of oxygen, subtract the mass of copper from the total mass.

0.143-0.1271=0.0159

There are 0.0159 grams of Oxygen.

To find how many moles there are, divide the given amount of oxygen by the molar mass (atomic mass) of oxygen because that mass is the same as one mole of oxygen.

Molar mass of Oxygen: 16.00

0.0159/16.00=9.94*10^{-4}

There are 9.94*10^-4 moles of Oxygen.

6 0
1 year ago
Name the homologous series for this compound and show its structure<br>ch3ch2cc(ch2)2ch3​
kotykmax [81]

Answer:

Alkyne

Explanation:

The homologous series for this compound is the Alkyne because of the presence of the triple bond present between the third and fourth carbon atoms as seen in the picture attached.

5 0
2 years ago
Dichlorine monoxide, Cl2O is sometimes used as a powerful chlorinating agent in research. It can be produced by passing chlorine
Amiraneli [1.4K]

Answer:

% yield =  82.5%

Explanation:

HgO + 2Cl₂ →  HgCl₂ +  Cl₂O

Our reactants are:

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Our products are:

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We do not have information about moles of reactants, but we do know the theoretical yield and the grams of product, in this case Cl₂O, we have produced.

Percent yield = (Yield produced / Theoretical yield) . 100

Theoretical yield is the mass of product which is produced by sufficent reactant. We replace data:

% yield = (0.71 g/0.86g) . 100 = 82.5%

7 0
3 years ago
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I think it is called a loess. Please correct me if I am wrong.

4 0
3 years ago
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kati45 [8]
The full chemical symbol for an element<span> shows its mass </span>number<span> at the top, and its atomic </span><span>number at the bottom</span>

7 0
3 years ago
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