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Gnesinka [82]
3 years ago
14

What element has the electrons configuration of [Ar]4s^2 3d^5

Chemistry
1 answer:
Scilla [17]3 years ago
5 0

Answer:

Manganese

Explanation:

Using rules you will find the location on 3d^5 because you subtract one level when in the d block

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What is the mass in grams of 33.3 moles of NaCl?
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33.3 moles of NaCI = 1946.144241 grams

Explanation:

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Nitrogen monoxide and water react to form ammonia and oxygen, like this: (g)(g)(g)(g) Write the pressure equilibrium constant ex
xxTIMURxx [149]

Answer:

Kp = \frac{P(NH_{3}) ^{4} P(O_{2}) ^{5}}{P(NO) ^{4} P(H_{2}O)^{6}}

Explanation:

First, we have to write the balanced chemical equation for the reaction. Nitrogen monoxide (NO) reacts with water (H₂O) to give ammonia (NH₃) and oxygen (O₂), according to the following:

NO(g) + H₂O(g) → NH₃(g) + O₂(g)

To balance the equation, we add the stoichiometric coefficients (4 for NH₃ and NO to balance N atoms, then 6 for H₂O to balance H atoms and then 5 for O₂ to balance O atoms):

4 NO(g) + 6 H₂O(g) → 4 NH₃(g) + 5 O₂(g)

All reactants and products are in the gaseous phase, so the equilibrium constant is expressed in terms of partial pressures (P) and is denoted as Kp. The Kp is expressed as the product of the reaction products (NH₃ and O₃) raised by their stoichiometric coefficients (4 and 5, respectively) divided into the product of the reaction reagents (NO and H₂O) raised by their stoichiometric coefficients (4 and 6, respectively). So, the pressure equilibrium constant expression is written as follows:

Kp = \frac{P(NH_{3}) ^{4} P(O_{2}) ^{5}}{P(NO) ^{4} P(H_{2}O)^{6}}

6 0
3 years ago
What is the molar mass of a compound?
Masteriza [31]

Answer:

The molar mass of a compound is The mass in grams of 1 mole of the compound (Option A)

Explanation:

Let's take ammonia as an example (NH3)

Mass of N = 14 g

Mass of H = 1 g

Molar mass of ammonia is Mass of N + (Mass of H).3

14 + 3 = 17 g/m

Ammonia is a compound that has 1 mol of N, plus 3 moles of H (see the formula)

The number of atoms in 1 mole of the compound --> This is Avogadro

7 0
2 years ago
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