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kogti [31]
3 years ago
8

When an electric stove element is hot enough, it gives off a dull red glow. When it cools to the point that it no longer glows,

it will.
Physics
1 answer:
DochEvi [55]3 years ago
4 0

Answer:

It will have a longer wavelength

Explanation:

When an electric stove is hot and gives dull red glow. a part of the energy dissipated is emitted as visible light and part as infrared radiation in the form of heat. When the stove cools down, and no longer glows all the energy is now in the form of infrared radiation.In the electromagnetic spectrum infrared rays have a higher wavelength than visible light. Hence for the reason the radiation will have a higher wavelength since visible light is cut off.

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What are 7 elements from the periodic table that are named after objects in outer space
suter [353]
Helium... from the greek word helios... the sun 
<span>selenium... from the greek word selene... the moon </span>
<span>palladium.. after the asteroid pallas </span>
<span>tellurium...from the greek word tellus... the earth </span>
<span>mercury...after the planet mercury </span>
<span>cerium... after the asteroid ceres </span>
<span>uranium...after the planet uranus </span>
<span>neptunium.. after the planet neptune </span>
<span>plutonium.. after the planet pluto</span>
5 0
3 years ago
The weight of an iron block is 8.0±0.3? and is placed on a wooden base of area, 3.5±0.2? 2. Calculate the pressure exerted by th
vesna_86 [32]

Answer:

Explanation:

Units...Nothing is accurate without UNITS. 8.0±0.3 lbs,? Newtons? 3.5±0.2 m²? ft²? cm²? km²? furlong²? fathoms²?

your answer will be  8.0±0.3 / 3.5±0.2  units / units²

8 0
2 years ago
The circumference of the Earth is approximately 40,000 km. The Earth has a magnetic field that protects it from solar particle r
olasank [31]

Answer:

All are correct except the age of earth. The age of Earth is approximately 4.543 Billion Years.

6 0
3 years ago
A mole of a monatomic ideal gas at point 1 (101 kPa, 5 L) is expanded adiabatically until the volume is doubled at point 2. Then
Paha777 [63]

Answer:

(a). Check attachment.

(b). 280.305 J.

(c). 31.81 kpa; 38.26K.

(d). 24.05K.

(e). 24.05k; 40kpa.

(f). -138.6J.

Explanation:

(a). Kindly check the attached picture for the diagram showing the four process.

1 - 2 = adiabatic expansion process.

2 - 3 = Isochoric process.

3 - 4 = isothermal process.

4 - 1 = isochoric process.

(b). Recall that the process from 1 to is an adiabatic expansion process.

NB: b = 5/3 for a monoatomic gas.

Then, the workdone = (1/ 1 - 1.66) [ (p1 × v1^b)/ v2^b × v2 - (p1 × v1)].

= ( 1/ 1 - 5/3) [ (101 × 5^5/3) × 10^1 -5/3] - 101 × 5.

Thus, the workdone = 280.305 J.

(c). P2 = P1 × V1^b/ V2^b = 101 × 5^5/3/ 10^5/3 = 31.81 kpa.

T2 = P2 × V2/ R × 1 = 31.81 × 10/ 8.324 = 38.36k.

(d). The process 2 - 3 is an Isochoric process, then;

T3 = T2/P2 × P3 = 38.26/ 31.82 × 20 = 24.05K.

(e). The process 3 - 4 Is an isothermal process. Then, the temperature at 4 will be the same temperature at 3. Tus, we have the temperature; point 3 = point 4 = 24.05k.

The pressure can be determine as below;

P4 = P3 × V3/ V4 = 20 × 10/ 5 = 200/ 5 = 40 kpa.

(f) workdone = xRT ln( v4/v3) = 1 × 8.314 × 24.05 × ln (5/10) = - 138.6 J

6 0
3 years ago
SOMEONE HELP ME PLEASE
mihalych1998 [28]

Explanation:

By the second law of Newton we get the relation

F = ma

5 0
2 years ago
Read 2 more answers
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