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3 years ago

5

HELPPPPPPPP PLSSSSSSSS A car moves with constant velocity along a straight road. Its position is x1 = 0 m at t1 = 0 s and is x2

= 66 m at t2 = 6.0 s . Answer the following by considering ratios, without computing the car's velocity.\ 1.What will be its position at t = 24 s ? 2.What is the car's position at t = 3.0 s ?

2 answers:

yawa3891 [41]3 years ago

6 0

Answer:

Explanation:

6.2 miles

vodka [1.7K]3 years ago

6 0

Answer: 1. 264, 2.33

Explanation: Explanation: <u>66m= 6s</u> so, to find the position at <u>3s</u> you just need to take 66<u>/2</u> = 33m cause <u>3 is half of 6</u>. & for 2 you will take 66<u>x4</u>= 264m cause it took <u>4s multiply by the original 6s to get 24s</u>. Answer: 1 is 264m & 2 is 33m.

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Answer:s=0.68 m

Explanation:

Given

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deceleration provided by friction=g\sin \theta -\mu _kg\cos \theta [/tex]

Using $v^2-u^2=2as$

Final velocity v=0

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3 years ago

The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is J. (Report the answer to two significant figu

abruzzese [7]

Answer:

$\boxed{\sf Kinetic \ energy \ (KE) = 85 \ J}$

Given:

Mass (m) = 6.8 kg

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To Find:

Kinetic energy (KE)

Explanation:

Formula:

$\boxed{ \bold{\sf KE = \frac{1}{2} m {v}^{2} }}$

Substituting values of m & v in the equation:

$\sf \implies KE = \frac{1}{2} \times 6.8 \times {5}^{2}$

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3 years ago

Read 2 more answers

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KonstantinChe [14]

Answer:

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From hf=eV

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f= frequency of the electromagnetic wave = 5.2×10^4 Hz

e= electronic charge= 1.6×10^-19 C

V= voltage

V= hf/e

V= 6.6×10^-34JS × 5.2×10^4 Hz/ 1.6×10^-19 C

V= 2.145×10^-10 V or 0.2145nV

Therefore the voltage created is 2.145×10^-10 V or 0.2145nV

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3 years ago

A high school bus travels 240 km in 6.0 h. What is its average speed for the trip? (in km/h).

KengaRu [80]

Answer:

40 km/h

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First...

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Use the formula: 240/6.0

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3 years ago

What force must the deltoid muscle provide to keep the arm in this position?

ruslelena [56]

Answer:

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Additional Information:

Some numerical information are missing from the question. However, I will derive the formula to calculate the force of the deltoid muscle. All you need to do is insert the necessary information and calculate.

Explanation:

The deltoid muscle is the one keeping the hand arm in position. We have two torques that apply to the rotating of the arm.

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2. The torque of the arm, $T_{arm}$

Assuming the arm is just being stretched and there is no rotation going on,

$T_{Deltoid}$ = 0

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Where,

$r_{d}$ is radius of the deltoid

$F_{d}$ is the force of the deltiod

$\alpha_{d}$ is the angle of the deltiod

$r_{a}$ is the radius of the arm

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$\alpha_{a}$ is the angle of the arm

The force of the deltoid muscle is,

$F_{d} = \frac {r_{a}F_{a}sin\alpha_{a}}{r_{d}sin\alpha_{d}}$

but $F_{a} = mg$ ,

∴ $F_{d} = \frac {r_{a}mgsin\alpha_{a}}{r_{d}sin\alpha_{d}}$

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