Answer:
27.22 m/s
Explanation:
Let the speed of clay before impact is u.
the speed of clay and target is v after impact.
use conservation of momentum
momentum before impact momentum after impact
mass of clay x u = (mass of clay + mass of target) x v
100 x u = (100 + 500) x v
u = 6 v .....(1)
distance, s = 2.1 m
μ = 0.5
final velocity is zero. use third equation of motion
v'² = v² + 2as
0 = v² - 2 x μ x g x s
v² = 2 x 0.5 x 9.8 x 2.1 = 20.58
v = 4.54 m/s
so by equation (1)
u = 6 x 4.54 = 27.22 m/s
thus, the speed of clay before impact is 27.22 m/s.
Answer:
0.1 m
Explanation:
It is given that,
Mass of the object, m = 350 g = 0.35 kg
Spring constant of the spring, k = 5.2 N/m
Amplitude of the oscillation, A = 10 cm = 0.1 m
Frequency of a spring mass system is given by :
Time period:
Answer:
the small one will have greater acceleration
Explanation:
force and mass are inversely proportional. force and acceleration are directly proportional. which means greater mass have smaller acceleration and smaller mass has greater acceleration. this is due to newtons second law of motion.
Answer:
the answers are 1 2 and 5!
Answer:
Resistance of the light bulb = 1.33 ohm (Approx.)
Explanation:
Given:
Current in electric bulb = 2 Amp
Voltage in battery = 1.5 Volt
Find:
Resistance of the light bulb
Computation:
Resistance = Voltage / Current
Resistance of the light bulb = Voltage in battery / Current in electric bulb
Resistance of the light bulb = 2 / 1.5
Resistance of the light bulb = 1.33 ohm (Approx.)
