HELPPPPPPPP PLSSSSSSSS A car moves with constant velocity along a straight road. Its position is x1 = 0 m at t1 = 0 s and is x2
2 answers:
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Answer: a) Moment = 200N.m
b) F = 500N
Explanation: <u>Moment</u> or <u>Torque</u> is the tendency of a body to rotate because of an aplplied force. It can be calculated as
F is force applied
r is distance from the force to the point of rotation
θ is the angle formed between force and distance
a) Since F and r are perpendicular, θ=90°, sin90° = 1, so
200
<u>Torque</u><u> caused by weight of the barrier at the pivot is </u><u>200N.m</u>
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b) Counterweight has the same torque as pivot: 200
So, to find Force necessary to balance the weight:
F = 500
<u>It is necessary </u><u>a force of 500N</u><u> from the counterweight to balance the weight.</u>
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Answer:
0.5
Explanation:
Data provided in the question:
The angle between their transmission axes, θ = 60°
Now,
We have the relation,
I₁ = I₀cos²θ
where,
I₁ is the intensity of the transmitted light
I₀ is the intensity of the incident light
on rearranging, we get
=cos²60°
or
=0.5