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Stella [2.4K]
4 years ago
6

Describe the Dark Ages of our universe.

Physics
1 answer:
fiasKO [112]4 years ago
4 0
When the universe<span> was young, there was a time when it was empty of the stars and galaxies and planets we see today. This basically means that there was a loss of energy in the universe.</span>
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A straight section of silver wire has a cross sectional area A=2.0 mm2. A total of 9.4×1018 electrons pass through the wire in 3
Sergio [31]

Answer:

8.08 x 10^-5 m

Explanation:

A = 2 mm^2 = 2 x 10^-6 m^2

Total number of electrons, N = 9.4 x 10^18

time, t = 3 s

n = 5.8 x 10^28 electrons/ m^3

Current, i = Q / t = N x e / t = (9.4 x 10^18 x 1.6 x 10^-19) / 3 = 0.5 A

Let vd be the drift velocity.

i = n e A vd

0.5 = 5.8 x 10^28 x 1.6 x 10^-19 x 2 x 10^-6 x vd

vd = 2.7 x 10^-5 m/s

Distance traveled by the electrons = velocity x time

                                                          = vd x t = 2.7 x 10^-5 x 3 = 8.08 x 10^-5 m  

3 0
3 years ago
Assuming the ball's initial velocity was 51 ∘ above the horizontal and ignoring air resistance, what did the initial speed of th
Umnica [9.8K]

horizontal distance of home run is 400 ft = 122 m

height of the home run is 3 ft = 0.9 m

now the angle of the hit is 51 degree

now we have equation of trajectory of the motion

x = vcos\theta * t

y = v sin\theta * t - \frac{1}{2} gt^2

solving above two equations we have

y = xtan\theta - \frac{gx^2}{2v^2cos^2\theta}

now here we will plug in all data

0.9 = 122 tan51 - \frac{9.8 * 122^2}{2*v^2 * cos^251}

0.9 = 150.65 - \frac{184150.2}{v^2}

\frac{184150.2}{v^2} = 149.75

v = 35.1 m/s

<em>so the ball was hit with speed 35.1 m/s from the ground</em>

8 0
3 years ago
Ahmed kept a balloon from his birthday for several days until it began to deflate and slowly sink to the ground. He wondered how
goldfiish [28.3K]
<span>He should study the chapter about laws to get a better understanding about the laws that govern physical objects</span>
8 0
3 years ago
Read 2 more answers
A satellite is in a circular orbit around a planet. A second satellite is placed in a different circular orbit that is farther a
irinina [24]

The speed of the second satellite is less than the speed of the first satellite.

<h3>What is speed?</h3>

The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.

Given is a satellite is in a circular orbit around a planet. A second satellite is placed in a different circular orbit that is farther away from the same planet.

When the distance from the center of the orbit increases, the time to complete the orbit will be greater.

Thus, the speed of the second satellite is less than the speed of the first satellite.

Learn more about speed.

brainly.com/question/7359669

#SPJ1

3 0
2 years ago
Assume that an intercontinental ballistic missile goes from rest to a suborbital speed of 6.50 km/s in 60.0 s (the actual speed
olasank [31]

Answer:

Average acceleration is (11.05)g\ m/s^2

Explanation:

It is given that,

Initial velocity, u = 0

Final velocity, v = 6.5 km/s = 6500 m/s

Time taken, t = 60 s

Acceleration, a=\dfrac{v-u}{t}

a=\dfrac{v}{t}  

a=\dfrac{6500\ m/s}{60}  

a=108.33\ m/s^2

Since, g=9.8\ m/s^2

So, a=(11.05)g\ m/s^2

So, the angular acceleration of the missile is (11.05)g\ m/s^2. Hence, this is the required solution.

4 0
3 years ago
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