Answer:
With any object at any time the free fall acceleration is 10 m/s2
Explanation:
That is because when you throw a ball into the air it decreases by about 10 m/s each second, on the way down it increases its speed by about 10 m/s each second. So the the anwser is 10 m/s2.
Answer:
The correct answer is:
(a) 84.240 kg
(b) 24.038 m
Explanation:
The given values are:
Force,
F = 81.0 N
Distance,
S = 13.0 m
Time,
t = 5.20 s
As we know,
The acceleration of mass will be:
⇒ ![a=\frac{2S}{t^2}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B2S%7D%7Bt%5E2%7D)
On substituting the given values, we get
⇒ ![=\frac{2\times 13.0}{(5.20)^2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%5Ctimes%2013.0%7D%7B%285.20%29%5E2%7D)
⇒ ![=\frac{26}{27.04}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B26%7D%7B27.04%7D)
⇒ ![=0.961538 \ m/s^2](https://tex.z-dn.net/?f=%3D0.961538%20%5C%20m%2Fs%5E2)
(a)
The mass of the block will be:
⇒ ![m=\frac{F}{a}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7BF%7D%7Ba%7D)
On substituting the given values, we get
⇒ ![=\frac{81.0}{0.961538}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B81.0%7D%7B0.961538%7D)
⇒ ![=84.240 \ kg](https://tex.z-dn.net/?f=%3D84.240%20%5C%20kg)
(b)
The final velocity after a given time i.e.,
t = 5.00 s
⇒ ![v=at](https://tex.z-dn.net/?f=v%3Dat)
On substituting the values, we get
⇒ ![=0.961538\times 5.00](https://tex.z-dn.net/?f=%3D0.961538%5Ctimes%205.00)
⇒ ![=4.8076 \ m/s](https://tex.z-dn.net/?f=%3D4.8076%20%5C%20m%2Fs)
In time, t = 5.00 s
The distance moved by the block will be:
⇒ ![d=vt](https://tex.z-dn.net/?f=d%3Dvt)
On putting the values, we get
⇒ ![=4.8076\times 5.00](https://tex.z-dn.net/?f=%3D4.8076%5Ctimes%205.00)
⇒ ![=24.038 \ m](https://tex.z-dn.net/?f=%3D24.038%20%5C%20m)
Answer: Speed = 4 m/s
Explanation:
The parameters given are
Mass M = 60 kg
Height h = 0.8 m
Acceleration due to gravity g= 10 m/s2
Before the man jumps, he will be experiencing potential energy at the top of the table.
P.E = mgh
Substitute all the parameters into the formula
P.E = 60 × 9.8 × 0.8
P.E = 470.4 J
As he jumped from the table and hit the ground, the whole P.E will be converted to kinetic energy according to conservative of energy.
When hitting the ground,
K.E = P.E
Where K.E = 1/2mv^2
Substitute m and 470.4 into the formula
470.4 = 1/2 × 60 × V^2
V^2 = 470.4/30
V^2 = 15.68
V = square root (15.68)
V = 3.959 m/s
Therefore, the speed of the man when hitting the ground is approximately 4 m/s
Sitting = no movement
KE=0