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frutty [35]
3 years ago
14

What unit is used to measure the period of a wave

Physics
1 answer:
zloy xaker [14]3 years ago
4 0

Answer:

seconds

Explanation: apex verified

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How much stronger is the gravitational pull of the sun on earth
Alex777 [14]
28 times stronger than the force of gravity on the surface of the Earth.
6 0
3 years ago
A 2.5 kg steel gasoline tank can holds 20.0 L of gasoline when full. What is the average density (in Kg/m^3) of the full gas can
yarga [219]

Answer:

D=792.3\ kg/m^3

Explanation:

<u>Average Density </u>

The density of an object of mass m and volume V is

\displaystyle D=\frac{m}{V}

If we know the density and the volume occupied by the object, the mass can be computed as

m=D.V

The tank can hold 20 L of gasoline when full. Converting to cubic meters

V_g=20*0.001=0.02\ m^3

That's the volume of the gasoline it contains. Knowing the density of the gasoline, we get the mass of gasoline.

m_g=680*0.02=13.6\ kg

To know the total mass of both, we add the 2.5 kg of the tank

m=m_t+m_g=13.6+2.5=16.1\ kg

The volume of the tank is computed solving for V

\displaystyle V=\frac{m}{D}

\displaystyle V_t=\frac{2.5}{7800}=3.205\times 10^{-4}\ m^3

The total volume is

V=V_g+V_t=0.02+3.205\times 10^{-4}=0.0203\ m^3

The average density is

\displaystyle D=\frac{16.1}{0.0203}

\boxed{D=792.3\ kg/m^3}

7 0
3 years ago
The amplitude of a lightly damped oscillator decreases by 3.42% during each cycle. What percentage of the mechanical energy of t
frozen [14]

Answer:

The percentage of the mechanical energy of the oscillator lost in each cycle is 6.72%

Explanation:

Mechanical energy (Potential energy, PE) of the oscillator is calculated as;

PE = ¹/₂KA²

During the first oscillation;

PE₁ = ¹/₂KA₁²

During the second oscillation;

A₂ = A₁ - 0.0342A₁ = 0.9658A₁

PE₂ = ¹/₂KA₂²

PE₂ = ¹/₂K (0.9658A₁)²

PE₂ = (0.9658²)¹/₂KA₁²

PE₂ = (0.9328)¹/₂KA₁²

PE₂ = 0.9328PE₁

Percentage of the mechanical energy of the oscillator lost in each cycle;

Change \ in \ percent= \frac{PE_2 - PE_1}{PE_1} \\\\Change \ in \ percent= \frac{0.9328PE_1 -PE_1}{PE_1} *100\\\\Change \ in \ percent= \frac{-0.0672PE_1}{PE_1}*100 \\\\Change \ in \ percent= -0.0672*100\\\\Change \ in \ percent= -6.72 \ \% \\\\Loss \ in \ percent= 6.72 \ \%

Therefore, the percentage of the mechanical energy of the oscillator lost in each cycle is 6.72%

4 0
3 years ago
How tall in cm is 5.4 feet
Digiron [165]
That is 164.592cm = 5.4 feet
3 0
4 years ago
Hii! help asap. i’ll give brainliest thanks!
o-na [289]

I believe it’s the mass of the box but I don’t no if I’m right

Hope this helped
5 0
3 years ago
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