This is a device used to change the flow of electricity through a circuit
2 answers:
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Answer:
It will take 20,000 seconds to get a pressure of 200Pa at the bottom of the tank.
Explanation:
The pressure at the bottom of the tank will be
where is the mass of the water, and
is the base area of the tank.
The base area of the tank is
,
and if we want the pressure at the bottom to be 200pa, then it must be that
,
solving for we get:
which is the required mass of the water in the tank.
Now, the tank fills at a rate of 2 drops per second or
since each drop weights 0.05g.
Therefore, the time it takes to collect 20kg of water will be
which is 55.56 hours or 2 days and 7.56 hours.
Thus, it will take 20,000 seconds to get a pressure of 200Pa at the bottom of the tank.
Answer:
a) F_net = 6.48 10⁻¹⁸ ( ), b) x = 0.15 m
Explanation:
a) In this problem we use that the electric force is a vector, that charges of different signs attract and charges of the same sign repel.
The electric force is given by Coulomb's law
F =
Since when we have the two negative charges they repel each other and when we fear one negative and the other positive attract each other, the forces point towards the same side, which is why they must be added.
F_net= ∑ F = F₁ + F₂
let's locate a reference system in the load that is on the left side, the distances are
left side - electron r₁ = x
right side -electron r₂ = d-x
let's call the charge of the electron (q) and the fixed charge that has equal magnitude Q
we substitute
F_net = k q Q ( )
F _net = kqQ ( )
let's substitute the values
F_net = 9 10⁹ 1.6 10⁻¹⁹ 4.50 10⁻⁹ ( )
F_net = 6.48 10⁻¹⁸ ( )
now we can substitute the value of x from 0.05 m to 0.25 m, the easiest way to do this is in a spreadsheet, in the table the values of the distance (x) and the net force are given
x (m) F (N)
0.05 27.0 10-16
0.10 8.10 10-16
0.15 5.76 10-16
0.20 8.10 10-16
0.25 27.0 10-16
b) in the adjoint we can see a graph of the force against the distance, it can be seen that it has the shape of a parabola with a minimum close to x = 0.15 m
