Answer:
326149.2 KJ
Explanation:
The heat transfer toward and object that suffered an increase in temperature can be calculated using the expression:
Q = m*cv*ΔT
Where m is the mass of the object, cv is the specific heat capacity at constant volume, which basically means the amount of heat necessary for a 1kg of water to increase 1C degree in temperatur, and ΔT is the change in temperature.
A 65000 L swimming pool will have a mass of:
65000L *
= 65000 kg
The specific heat capacity at constant volume of water is equal to 4.1814 KJ/KgC.
We replace the data and get:
Q = m*cv*ΔT = 65000 kg * 4.1814 KJ/KgC * 1.2°C = 326149.2 KJ
Answer:
Flow rate of air is given as 83.33 cubic feet per minute
Explanation:
As we know that total volume of the air flow is given as
also we know that total time is
now we have flow rate given as
Answer:
The given figure shows two men M and N facing two flat and hard walls, wall 1 and wall 2. Man N fires a gun. Man M hears two echoes, one from wall 1 and second from wall 2. The speed of sound in
air is given to be 325 m/s. After the firing of the gun by the man N, the man M will hear the first echo in how many seconds?
Answer:
46°C
Explanation:
q = mCΔT
336,000 J = (20 kg) (4200 J/kg/°C) (50°C − T)
T = 46°C
Answer:
Answer
The Final Quality of teh R-134a in the container is 0.5056
The Total Heat transfer is 
Explanation:
Explanation is in the following attachments
