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3 years ago

8

What is an example of tipping point?

2 answers:

tensa zangetsu [6.8K]3 years ago

6 0

Answer:Examples of tipping points are everywhere: a glass falling off a table upon tilting; a bacterial population hitting a level where it pushes your body into fever; the boiling point of water, or a cube of ice being thrown into warm water, where it rapidly melts.

Explanation:

sladkih [1.3K]3 years ago

3 0

<u>Answer:</u>

<em>A IPCC AR5 climate tipping point is a critical stage at which global or regional climate shows a major change. </em>

<u>Explanation:</u>

The atmosphere framework expresses that the exact degrees of environmental change adequate to trigger a tipping point stay unsure, yet that the hazard related to intersection different tipping focuses increments with rising temperature.

Examples are melting of Arctic sea, Collapse of coral leaf due to global warming, eutrophication of the lake, Forest loss, lack of rain, Ocean warming, changes in the temperature of the Ocean current etc.

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Balance the equation: Ca + ....... H2O->Ca(OH)2 + H2

Mnenie [13.5K]

$\large\boxed{{Ca+ \bold{2}H_2O \to Ca(OH)_2+H_{2}}}$

7 0

4 years ago

When adding the measurements 42.1014 g + 190.5 g, the answer has ___ significant figures.

andrezito [222]

Answer: The answer has 7 significant figures

Explanation:

The addition of 190.5 and 42.1014 will give 232.6014. Counting the digits will give 7 significant figures.

4 0

4 years ago

An object was measured by a worker as 17.4cm long, however, the manufacturer specifications list the length of the object at 17.

Olin [163]

Answer:

Percent error = 2.8

Explanation:

Given data;

Actual value = 17.9 cm

Measured value = 17.4 cm

Percent error = ?

Solution:

Formula:

Percent error = [actual value - measured value / actual value] × 100

Now we will put the values in formula:

Percent error = [17.9 cm - 17.4 cm / 17.9 cm] × 100

Percent error = [0.5 cm /17.9 cm] × 100

Percent error = 0.028 × 100

Percent error = 2.8

5 0

3 years ago

A sample of gas occupies a volume of 50.0 milliliters in a cylinder with a movable piston. The pressure of the sample is 0.90 at

solong [7]

Answer:

The volume of sample at STP is = 41.22 ml

Explanation:

Given data

$P_{1}$ = 0.9 atm

$V_{1}$ = 50 ml

$T_{1}$ = 298 K

At STP

$P_{2}$ = 1 atm

$T_{2}$ = 273 K

From ideal gas equation

$\frac{P_1(V_1)}{T_1} = \frac{P_2(V_2)}{T_2}$

$\frac{(0.9)(50)}{298} = \frac{(1) V_2}{273}$

$V_2$ = 41.22 ml

Therefore the volume of sample at STP is = 41.22 ml

4 0

3 years ago

A sample of a gas in a rigid cylinder with a movable piston has a volume of 11.2 liters at STP. What is the volume of this gas a

posledela

Given that the volume of cylinder at STP = 11.2 L

Standard temperature = 273 K

Standard pressure = 1 atm

Calculating the volume of gas at 202.6 kPa and 300. K:

Applying the combined gas law,

$\frac{P_{1}V_{1}}{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}$

$P_{1} =1 atm$

$V_{1}=11.2 L$

$T_{1}=273K$

$P_{2}$ = $202.6 kPa*\frac{1 atm}{101.325 kPa} =2 atm$

$V_{2}= ?$

$T_{2}=300. K$

Plugging in the values and calculating final volume:

$\frac{(1atm)(11.2L)}{(273 K)} =\frac{(2atm)(V_{2})}{(300K)}$

$V_{2}=6.15 L$

Therefore the correct answer will be, b) 6.15 L

6 0

3 years ago