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3 years ago

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At the equator, near the surface of Earth, the magnetic field is approximately 80.0 μT northward and the electric field is about

150 N/C downward in fair weather. Find the gravitational, electric, and magnetic forces on an electron with instantaneous velocity of 6.00 106 m/s directed to the east in this environment.

1 answer:

lys-0071 [83]3 years ago

8 0

Answer:

Gravitational force = 89.18 x 10^-31 N

Electric force = 2.4 x 10^-17 N

Magnetic force = 7.68 x 10^-17 N

Explanation:

B = 80 micro tesla = 80 x 10^-6 T north

E = 150 N/C downward

v = 6 x 10^6 m/s east

Gravitational force = m g = 9.1 x 10^-31 x 9.8 = 89.18 x 10^-31 N

Electric force = q E = 1.6 x 10^-19 x 150 = 2.4 x 10^-17 N

Magnetic force = q v B Sin 90 = 1.6 x 10^-19 x 6 x 10^6 x 80 x 10^-6

= 7.68 x 10^-17 N

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Answer:

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3 years ago

The density of gasoline is 730 kg/m3 at 0°C. Its average coefficient of volume expansion is 9.60 10-4(°C)−1. Assume 1.00 gal of

kipiarov [429]

Answer: 0.4911 kg

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Now, we have to calculate the factor $f$ by which the volume of gasoline is increased with the temperature, which is given by:

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Where $T_{o}=0\°C$ is the initial temperature and $T_{f}=21.7\°C$ is the final temperature.

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