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2 years ago

Which of the following are likely to form a covalent bond?

Chemistry

2 answers:

ohaa [14]2 years ago

6 0

Answer: The correct answer is Option C.

Explanation:

A covalent bond is defined as the bond which is formed when sharing of electrons takes place between the atoms forming a compound. This type of bond is usually formed between two non-metals.

From the given options:

Option A: two gold atoms

Gold atom is a metal and thus, will not form covalent bond.

Option B: two neon atoms

Neon atom is a noble gas and is unreactive atom. Thus, it will not form covalent bond.

Option C: hydrogen and oxygen atoms

Both the atoms are non-metals and thus, will lead to the formation of a covalent bond.

Option D: magnesium and bromine atom

Magnesium atom is a metal and bromine atom is a non-metal. Thus, they will not lead to the formation of covalent bond but will form ionic bond.

Hence, the correct answer is Option C.

Alex17521 [72]2 years ago

5 0

C) hydrogen and oxygen atoms

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*multiple choice*

OleMash [197]

I think the answer is A but I could be wrong

4 0

2 years ago

A chemical reaction was carried out by mixing 25 g of pure CaCO3 and 0.75 mole of pure HCl to give CaCl2, H2O and CO2. a. Which

Naily [24]

hola, esta pregunta es bastante difícil pero está bien, no lo sé, lo siento :) :)

4 0

3 years ago

When neurotransmitter is released into the synaptic cleft, it is taken up by the post-synaptic neuron.

gogolik [260]

Answer:

Plz make me brainliest

Explanation:

The neurotransmitters released into the cleft diffuse through it to reach the post-synaptic neuron. Neurotransmitters remain in cleft for only some time. They are either taken up by the presynaptic neuron or are broken down by the enzymes present in the synaptic cleft. The post-synaptic neuron contains several receptors on its plasma membrane

7 0

3 years ago

A 0.1510 gram sample of a hydrocarbon produces 0.5008 gram CO2 and 0.1282 gram H2O in combustion analysis. Its

Over [174]

In a combustion of a hydrocarbon compound, 2 reactions are happening per element:

C + O₂ → CO₂
2 H + 1/2 O₂ → H₂O

Thus, we can determine the amount of C and H from the masses of CO₂ and H₂O produced, respectively.

1.) Compute for the amount of C in the compound. The data you need to know are the following:
Molar mass of C = 12 g/mol
Molar mass of CO₂ = 44 g/mol
Solution:
0.5008 g CO₂*(1 mol CO₂/ 44 g)*(1 mol C/1 mol CO₂) = 0.01138 mol C
0.01138 mol C*(12 g/mol) = 0.13658 g C

Compute for the amount of H in the compound. The data you need to know are the following:
Molar mass of H = 1 g/mol
Molar mass of H₂O = 18 g/mol
Solution:
0.1282 g H₂O*(1 mol H₂O/ 18 g)*(2 mol H/1 mol H₂O) = 0.014244 mol H
0.014244 mol H*(1 g/mol) = 0.014244 g H

The percent composition of pure hydrocarbon would be:
Percent composition = (Mass of C + Mass of H)/(Mass of sample) * 100
Percent composition = (0.13658 g + 0.014244 g)/(0.1510 g) * 100
Percent composition = 99.88%

2. The empirical formula is determined by finding the ratio of the elements. From #1, the amounts of moles is:

Amount of C = 0.01138 mol
Amount of H = 0.014244 mol

Divide the least number between the two to each of their individual amounts:
C = 0.01138/0.01138 = 1
H = 0.014244/0.01138 = 1.25

The ratio should be a whole number. So, you multiple 4 to each of the ratios:
C = 1*4 = 4
H = 1.25*4 = 5

Thus, the empirical formula of the hydrocarbon is C₄H₅.

3. The molar mass of the empirical formula is

Molar mass = 4(12 g/mol) + 5(1 g/mol) = 53 g/mol
Divide this from the given molecular weight of 106 g/mol
106 g/mol / 53 g/mol = 2
Thus, you need to multiply 2 to the subscripts of the empirical formula.

Molecular Formula = C₈H₁₀

4 0

3 years ago

1. What is the relation between distance and speed?

Inga [223]

Answer:

option no b is right answer

6 0

2 years ago