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alina1380 [7]
3 years ago
7

what elements would you expect to lose electrons in chemical changes? Potassium, sulfur, fluorine, barium or copper.

Chemistry
2 answers:
Hatshy [7]3 years ago
8 0
Potassium, Barium, and Copper because they are metals, and most metals tend to lose electrons when forming an ion.
Dvinal [7]3 years ago
8 0

Answer:

Potassium, barium, copper

Explanation:

Atomic number of potassium = 19

Electronic configuration of potassium =1s^22s^22p^63s^23p^64s^1

By loosing one electrons, it attains noble gas configuration.

Atomic number of sulphur = 16

Electronic configuration of sulphur = 1s^22s^22p^63s^23p^4

In order to attain noble gas configuration, it has to looses 6 electrons which is not favorable. So, sulphur gains electrons instead of loosing.

Atomic number of fluorine = 9

Electronic configuration of fluorine = 1s^22s^22p^5

Fluorine easily attains inert gas configuration by gaining 1 electron.

Atomic number of barium = 56

Electronic configuration of barium = [Xe]6s^2

Barium attains its noble gas configuration by loosing two electrons.

Atomic number of copper = 29

Electronic configuration of copper = [Ar]3d^{10}4s^1

Copper looses one electrons and attains stability. this is because elements having fully filled or half filled sub shell are stable.

So, among given, potassium, barium and copper are expected to lose electrons during chemical changes.

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Identify this reaction.
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<h3>Answer:</h3>

Single displacement reaction

<h3>Explanation:</h3>
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A galvanic cell consists of one half-cell that contains Ag(s) and Ag+(aq), and one half-cell that contains Cu(s) and Cu2+(aq). W
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Answer : The 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Explanation :

Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the voltaic cell or electrochemical cell.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

We are taking the value of standard reduction potential form the standard table.

E^0_{[Ag^{+}/Ag]}=+0.80V

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In this cell, the component that has lower standard reduction potential gets oxidized and that is added to the anode electrode. The second forms the cathode electrode.

The balanced two-half reactions will be,

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Reduction half reaction (Cathode) : Ag^{+}(aq)+e^-\rightarrow Ag(s)

Thus the overall reaction will be,

Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

From this we conclude that, 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

Hence, the 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.

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