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alina1380 [7]
3 years ago
7

what elements would you expect to lose electrons in chemical changes? Potassium, sulfur, fluorine, barium or copper.

Chemistry
2 answers:
Hatshy [7]3 years ago
8 0
Potassium, Barium, and Copper because they are metals, and most metals tend to lose electrons when forming an ion.
Dvinal [7]3 years ago
8 0

Answer:

Potassium, barium, copper

Explanation:

Atomic number of potassium = 19

Electronic configuration of potassium =1s^22s^22p^63s^23p^64s^1

By loosing one electrons, it attains noble gas configuration.

Atomic number of sulphur = 16

Electronic configuration of sulphur = 1s^22s^22p^63s^23p^4

In order to attain noble gas configuration, it has to looses 6 electrons which is not favorable. So, sulphur gains electrons instead of loosing.

Atomic number of fluorine = 9

Electronic configuration of fluorine = 1s^22s^22p^5

Fluorine easily attains inert gas configuration by gaining 1 electron.

Atomic number of barium = 56

Electronic configuration of barium = [Xe]6s^2

Barium attains its noble gas configuration by loosing two electrons.

Atomic number of copper = 29

Electronic configuration of copper = [Ar]3d^{10}4s^1

Copper looses one electrons and attains stability. this is because elements having fully filled or half filled sub shell are stable.

So, among given, potassium, barium and copper are expected to lose electrons during chemical changes.

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Answer:

1000L

Explanation:

the 1 is a sig fig and since the 0 is between the 1 and 4 its also a significant number. to round them off you look at the 0,then look back at the 4 since its less than 5 u round down. then u replace the 43 with 0's

3 0
3 years ago
When Earth’s axis points away from the sun, the _________ Hemisphere has the longer days of summer.
Llana [10]

Answer: northern hemisphere

Explanation: I looked it up. Plus I took a test with this question and when the teacher went over the answer i got it right.

3 0
2 years ago
1.15 g of a metallic element needs 300 cm3 of oxygen for complete reaction, at 298 K and 1 atm
sashaice [31]
1) Calculate the number of moles of O2 (g) in 300 cm^3 of gas at 298 k and 1 atm


Ideal gas equation: pV = nRT => n = pV / RT


R = 0.0821 atm*liter/K*mol

V = 300 cm^3 = 0.300 liter

T = 298 K

p = 1 atm


=> n = 1 atm * 0.300 liter / [ (0.0821 atm*liter /K*mol) * 298K] = 0.01226 mol


2) The reaction of a metal with O2(g) to form an ionic compound (with O2- ions) is of the type


X (+) + O2 (g) ---> X2O          or   


2 X(2+) + O2(g) ----> X2O2 = 2XO     or


4X(3+) + 3O2(g) ---> 2X2O3


 
In the first case, 1 mol of metal react with 1 mol of O2(g); in the second case, 2 moles of metal react with 1 mol of O2(g); in the third, 4 moles of X react with 3 moles of O2(g)



So, lets probe those 3 cases.


3) Case 1: 1 mol of metal X / 1 mol O2(g) = x moles / 0.01226 mol

=> x = 0.01226 moles of metal X


Now you can calculate the atomic mass of the hypotethical metal:

1.15 grams / 0.01226 mol = 93.8 g / mol


That does not correspond to any of the metal with valence 1+


So, now probe the case 2.



4) Case 2:


2moles X metal / 1 mol O2(g) = x / 0.01226 mol


=> x = 2 * 0.01226 = 0.02452 mol


And the atomic mass of the metal is: 1.15 g / 0.02452 mol = 46.9 g/mol


That is similar to the atomic mass of titanium which is 47.9 g / mol and whose valece is 2+.


4) Case 3


4 mol meta X / 3 mol O2 = x / 0.01226 => x = 0.01226 * 4 / 3 = 0.01635 


atomic mass = 1.15 g / 0.01635 mol = 70.33 g/mol


That does not correspond to any metal.


Conclusion: the identity of the metallic element could be titanium.
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What is the relationship between concentration and rate of reaction?
grigory [225]
<h3><u>Answer;</u></h3>

Directly proportional

<h3><u>Explanation;</u></h3>
  • <em><u>Concentration is one of the factors that determine the rate of a reaction. Reaction rates increases with increase in the concentration of the reactants, which means they are directly proportional.</u></em>
  • An increase in the concentration of reactants produces more collisions and thus increasing the rate at which the reaction is taking place. Therefore, <u>Increasing the concentration of a reactant increases the frequency of collisions between reactants and will cause an increase in the rate of reaction.</u>
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