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3 years ago

How can you separate a mixture of 10 grams of salt and 10 grams of sand?

1 answer:

8 0

Step 1.) Put both contents into a small cup or bowl.

Step 2.) Pour water into the cup or bowl.

Step 3.) Stir the contents.

10 grams of salt and 10 grams of sand can be separated by adding water into the mixture. Once you stir the mixture, the salt will dissolve into the water.

You might be interested in

Plain electromagnetic wave (in air) has a frequency of 1 MHz and its B-field amplitude is 9 nT a. What is the wavelength in air?

Norma-Jean [14]

Answer:

Part a)

$\lambda = 300 m$

Part b)

$E = 2.7 N/C$

Part c)

$I = 9.68 \times 10^{-3} W/m^2$

$P = 3.22 \times 10^{-11} N/m^2$

Explanation:

Part a)

As we know that frequency = 1 MHz

speed of electromagnetic wave is same as speed of light

So the wavelength is given as

$\lambda = \frac{c}{f}$

$\lambda = \frac{3\times 10^8}{1\times 10^6}$

$\lambda = 300 m$

Part b)

As we know the relation between electric field and magnetic field

$E = Bc$

$E = (9 \times 10^{-9})(3\times 10^8)$

$E = 2.7 N/C$

Part c)

Intensity of wave is given as

$I = \frac{1}{2}\epsilon_0E^2c$

$I = \frac{1}{2}(8.85 \times 10^{-12})(2.7)^2(3\times 10^8)$

$I = 9.68 \times 10^{-3} W/m^2$

Pressure is defined as ratio of intensity and speed

$P = \frac{I}{c} = \frac{9.68\times 10^{-3}}{3\times 10^8}$

$P = 3.22 \times 10^{-11} N/m^2$

6 0

3 years ago

Dejamos caer un objeto desde lo alto de una torre y medimos el tiempo que tarda en llegar al suelo que resulta ser de 0,02 minut

Harman [31]

Answer: a) 11.76 m/s b) 7.056 m

Explanation:

The described situation is as follows:

An object is dropped from the top of a tower and when measuring the time it takes to reach the ground that turns out to be 0.02 minutes.

This situation is related to free fall, this also means we have constant acceleration, hence the equations we will use are:

$V_{f}=V_{o}+at$ (1)

${V_{f}}^{2}={V_{o}}^{2}+2ad$ (2)

Where:

$V_{f}$ Is the final velocity of the object

$V_{o}=0$ Is the initial velocity of the object (it was dropped)

$a=9.8 m/s^{2}$ is the acceleration due gravity

$d$ is the height of the tower

$t=0.02min=1.2 s$ is the time it takes to the object to reach the ground

b) Begining with (1):

$V_{f}=0+at$ (3)

$V_{f}=at=(9.8 m/s^{2})(1.2 s)$ (4)

$V_{f}=11.76 m/s$ (5) This is the final velocity of the object

a) Substituting (5) in (2):

$(11.76 m/s)^{2}=0+2(9.8 m/s^{2})d$ (6)

Clearing $d$ :

$d=\frac{(11.76 m/s)^{2}}{2(9.8 m/s^{2})}$ (7)

$d=7.056 m$ (8) This is the height of the tower

4 0

3 years ago

What is the formula for displacement

pogonyaev

Displacement is usually given to you as it is, but you can also get displacement through velocity by Δd= Δv*t, where <span>Δv is the change in velocity and t is the change in time.

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4 0

3 years ago

How fast and in what direction must galaxy A be moving 17 an absorption Line found at 500 nm for a stationary galaxy 1s shifted

emmainna [20.7K]

Answer:

v = 0.22 c and wavelength is decrease so galaxy A is move away from stationary galaxy

v = 0.095 c and wavelength is increase so galaxy B come toward stationary galaxy

Explanation:

Given data

found = 500 nm

shifted A = 400 nm

shifted B = 550 nm

to find out

How fast and in what direction is galaxy

solution

we use here formula that is

(λ) shifted = √(1-β / 1+β) (λ)found

1-β / 1+β = (4/5)² ..................1

1-β / 1+β = 16 / 25

β = 0.22

v/c = 0.22

v = 0.22 c

here wavelength is decrease so galaxy A is move away from stationary galaxy

and

here according to equation 1

and we use shifted 550 nm

1-β / 1+β = (5.5/5)²

1-β / 1+β = 30.25 / 25

β = 0.095

so v/c = 0.095

v = 0.095 c

here wavelength is increase so galaxy B come toward stationary galaxy

3 0

3 years ago

How far will a beam of laser light travel in 70.4 nanoseconds?

Yuki888 [10]

Answer:

62 nanoseconds

Explanation:

7 0

2 years ago