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Alina [70]
4 years ago
6

Technician A says that bursting of clutch friction facings is often caused by coasting a truck with the clutch pedal depressed.

Technician B says that a clutch pressure plate with warpage sufficient to insert a 0.003 inch thickness gauge under a straight edge must be replaced. Who is correct?
Physics
1 answer:
7nadin3 [17]4 years ago
5 0

Answer: the answer is A. Bursting of clutch friction is often caused by coasting a truck with the clutch pedal depressed. Coasting most frequently occurs when keeping the clutch depressed while turning at intersections, dressing the pedal too soon before coming to a stop at a stop sign or traffic lights, or keeping the pedal depressed too long after a gear change.

Explanation: A clutch is a mechanical device which engages and disengages power transmission especially from driving shaft to driven shaft. Broken clutch plate facings are caused by incorrect driving practice or incorrect installation procedure.

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How much energy is needed to melt 5 g of ice? The specific latent heat of melting for water is 334000 J/k
777dan777 [17]

Answer:

2500 farenhight degrees

Explanation:

5 0
3 years ago
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A circular loop of wire with a radius of 12.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magne
kirza4 [7]

Answer:

The average induced emf is 29.06 V

Explanation:

Given;

radius of the circular loop, r = 12.0 cm = 0.12 m

magnetic field strength, B =  1.8 T

time interval = 2.8 ms = 0.0028 s

Area of the circular loop, A = πr² = π (0.12)² = 0.0452 m²

e.m.f =\frac{BA}{t}

where;

B is magnetic field

A is area

t is time

substitute the values given in the above equation to calculate the average emf that will be induced in the wire loop during the extraction process.

e.m.f =\frac{1.8 *0.0452}{0.0028} = 29.06 \ V

Therefore, the average induced emf is 29.06 V

5 0
3 years ago
Why does conservation of energy not result in perpetual motion machines?
Colt1911 [192]
The first law of thermodynamics is the law of conservation of energy. It states that energy is always conserved. ... To keep a machine moving, the energy applied should stay with the machine without any losses. Because of this fact alone, it is impossible to build perpetual motion machines.
5 0
3 years ago
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A circular copper wire is put in tension under a weight of 7000N. What is the ratio of its diameter after and before the load is
zaharov [31]

Answer:

\frac{d_f}{d} =0.9999983

Explanation:

Given:

  • force applied on the copper wire, F=7000\ N
  • cross sectional area of the wire, a=0.01\ m^2
  • Poisson's ratio, \mu=0.3
  • we have, Young's modulus, E=128\times 10^3\ MPa

<u>Stress induced due to the applied force:</u>

\sigma=\frac{F}{a}

\sigma=\frac{7000}{0.01}

\sigma=700000\ Pa=0.7\ MPa

<u>Now the longitudinal strain:</u>

<u />\epsilon=\frac{\sigma}{E}<u />

<u />\epsilon=\frac{0.7}{128\times 10^3}<u />

<u />\epsilon=5.468\times 10^{-6}<u />

Now from the relation of Poisson's ratio:

\mu=\frac{\nu}{\epsilon}

where:

\nu= lateral strain

0.3=\frac{\nu}{5.468\times 10^{-6}}

\nu=1.6406\times 10^{-6} ..................(1)

<u>Now we find the diameter of the wire:</u>

a=\pi.\frac{d^2}{4}

0.01=\pi\times \frac{d^2}{4}

\frac{0.04}{\pi} =d^2

d=0.1128\ m=112.8\ mm

<u>When the tensile load is applied its diameter decreases:</u>

The lateral strain is also given as,

\nu=\frac{\Delta d}{d}

1.6406\times 10^{-6}=\frac{\Delta d}{112.8}

\Delta d=0.000185\ mm

Now the final diameter will be:

d_f=d-\Delta d

d_f=112.8-0.000185

d_f=112.799815\ mm

Now the ratio:

\frac{d_f}{d} =\frac{112.799815}{112.8}

\frac{d_f}{d} =0.9999983

6 0
3 years ago
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8 0
4 years ago
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