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Alina [70]
4 years ago
6

Technician A says that bursting of clutch friction facings is often caused by coasting a truck with the clutch pedal depressed.

Technician B says that a clutch pressure plate with warpage sufficient to insert a 0.003 inch thickness gauge under a straight edge must be replaced. Who is correct?
Physics
1 answer:
7nadin3 [17]4 years ago
5 0

Answer: the answer is A. Bursting of clutch friction is often caused by coasting a truck with the clutch pedal depressed. Coasting most frequently occurs when keeping the clutch depressed while turning at intersections, dressing the pedal too soon before coming to a stop at a stop sign or traffic lights, or keeping the pedal depressed too long after a gear change.

Explanation: A clutch is a mechanical device which engages and disengages power transmission especially from driving shaft to driven shaft. Broken clutch plate facings are caused by incorrect driving practice or incorrect installation procedure.

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Give an example of how friction can be used and an example of how friction can be harmful
DaniilM [7]

Answer:

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A small bolt with a mass of 33.0 g sits on top of a piston. The piston is undergoing simple harmonic motion in the vertical dire
densk [106]

Answer:

0.027m

Explanation:

the bolt loses contact with the piston only when acceleration due to gravity equals acceleration of piston

ω² * A = g where ω is angular velocity, A amplitude, g acceleration due to gravity

ω is given by 2πf, ω² is 4π²f²

A= g/4π²f² depending on the value of g used either 10m/s² or 9.8m/s²,

i used 10m/s² in this answer

5 0
4 years ago
. A huge pile of leaves was wrapped in a tarp in the middle of a lawn. The wrapped leaves weigh 580 newtons. The coefficient of
Rina8888 [55]

The force required is 319 N

Explanation:

The force of static friction is a force that acts an object on a surface, when this object is pushed by another force to put it in motion. The direction of the force of friction is opposite to the direction of the force of push, and its value increases as the force of push increases, up to a maximum value given by:

F_f = \mu W

where

\mu is the coefficient of friction

W is the weight of the object

Therefore, in order to put the object in motion, the force applied must be greater than this value.

For the pile of leaves in this problem, we have:

\mu = 0.55 (coefficient of friction)

W=580 N (weight of the leaves)

Substituting, we find:

F=(0.55)(580)=319 N

Learn more about force of friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

7 0
4 years ago
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