Answer:
The average induced emf is 29.06 V
Explanation:
Given;
radius of the circular loop, r = 12.0 cm = 0.12 m
magnetic field strength, B = 1.8 T
time interval = 2.8 ms = 0.0028 s
Area of the circular loop, A = πr² = π (0.12)² = 0.0452 m²

where;
B is magnetic field
A is area
t is time
substitute the values given in the above equation to calculate the average emf that will be induced in the wire loop during the extraction process.

Therefore, the average induced emf is 29.06 V
The first law of thermodynamics is the law of conservation of energy. It states that energy is always conserved. ... To keep a machine moving, the energy applied should stay with the machine without any losses. Because of this fact alone, it is impossible to build perpetual motion machines.
Answer:

Explanation:
Given:
- force applied on the copper wire,

- cross sectional area of the wire,

- Poisson's ratio,

- we have, Young's modulus,

<u>Stress induced due to the applied force:</u>



<u>Now the longitudinal strain:</u>
<u />
<u />
<u />
<u />
<u />
<u />
Now from the relation of Poisson's ratio:

where:
lateral strain

..................(1)
<u>Now we find the diameter of the wire:</u>




<u>When the tensile load is applied its diameter decreases:</u>
The lateral strain is also given as,



Now the final diameter will be:



Now the ratio:


For the answer to the question above asking to d<span>etermine the density of the proton.
</span>Density is mass over volume.
The volume of a sphere is 4πr³/3. r is half the diameter.
So the density would be 2.3×10¹⁷ kg/m³.
I hope my answer helped you. Feel free to ask more questions. Have a nice day!