Answer:
acceleration = 0.2625 m/s²
Explanation:
acceleration = ( final velocity - initial velocity ) / time
Here the final velocity is 10.6 m/s and initial velocity is 6.4 m/s and time is 16 s.
using the equation:
acceleration = ( 10.6 - 6.4 ) / 16
= 0.2625 m/s²
Formula for Velocity = DISTANCE traveled/TIME to travel distance + direction
For this one, we can use mph(miles per hour) as unit.
v = 1,000 miles / 336 hours (2 weeks = 24 hours x 14 days = 336 hrs)
= 2.98 mph North
or we can use kph (kilometers per hour)
v = 1609.34 km / 336 hours (1 mile = 1.60934 km)
= 4.79 kph North
Ah hah ! There's an easy way and a hard way to do this one.
If it's OK with you, I'm gonna do it the easy way, and not even
talk about the hard way !
First, let's look at a few things in this question.
-- "gravitational force between a planet and a mass"
This is just a complicated way to say "How much does the mass weigh ?"
That's what we have to find.
-- If we know the mass, how do we find the weight ?
Multiply the mass by the acceleration of gravity there.
Weight = (mass) x (gravity) .
-- Do we know the acceleration of gravity on this dark mysterious planet ?
We do if we read the second line of the question !
It's right there ... 8.8 m/s² .
-- We know the mass. We know gravity. And we know that
if you multiply them, you get the weight (forced of gravity).
I'm pretty sure that you can do the rest of the solution now.
weight = (mass) x (gravity)
Weight = (17 kg) x (8.8 m/s²)
Multiply them:
Weight = 149.6 kg-m/s²
That complicated-looking unit is the definition of a Newton !
So the weight is 149.6 Newtons. That's the answer. It's choice-A.
It's about 33.6 pounds.
When this mass is on the Earth, it weighs about 37.5 pounds.
But when it's on this planet, it only weighs about 33.6 pounds.
That's because gravity is less on this planet. (8.8 there, 9.8 on Earth)
Answer:

Explanation:
The equation for the linear impulse is as follows:

where
is impulse,
is the force, and
is the change in time.
The force, according to Newton's second law:

and since 
the force will be:

replacing in the equation for impulse:

we see that
is canceled, so

And according to the problem
,
and the mass of the passenger is
. Thus:



the magnitude of the linear impulse experienced the passenger is 