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nadya68 [22]
2 years ago
14

The metal wire in an incandescent lightbulb glows when the lights is switch on and stops glowing when switched off. This simple

process is which kind of a change?
Physics
2 answers:
Radda [10]2 years ago
7 0

Opening or closing a circuit.

lutik1710 [3]2 years ago
4 0

Answer:

When the metal wire in an incandescent lightbulb glows when the light is switched on and stops glowing when it is switched off, this is an example of resistance, which provides light and heat.  

Explanation:

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A wind is blowing a small ice fishing shed along the ice to the east with a 800N force. The shed weighs 2,200N. What would the l
e-lub [12.9K]

Answer:

0.36

Explanation:

The maximum force of friction exerted by the surface is given by:

F_f = \mu N (1)

where

\mu is the coefficient of friction

N is the normal reaction

The shed's weight is 2200 N. Since there is no motion along the vertical direction, the normal reaction is equal and opposite to the weight, so

N = 2200 N

The horizontal force that is pushing the shed is

F = 800 N

In order for it to keep moving, the force of friction (which acts horizontally in the opposite direction) must be not greater than this value. So the maximum force of friction must be

F_f = 800 N

And substituting the values into eq.(1), we can find the maximum value of the coefficient of friction:

\mu = \frac{F_f}{N}=\frac{800}{2200}=0.36

6 0
3 years ago
A charge Q is placed on the x axis at x = +4.0 m. A second charge q is located at the origin. If Q = +75 nC and q = −8.0 nC, wha
Stells [14]

Answer:

23.1 N/C

Explanation:

OP = 3 m , OQ = 4 m

PQ = \sqrt{4^{2}+3^{2}}=5 m

q = - 8 nC, Q = 75 nC

Electric field at P due to the charge Q is

E_{1}=\frac{KQ}{PQ^{2}}=\frac{9\times 10^{9}\times 75\times 10^{-9}}{25}=27 N/C

Electric field at P due to the charge q is

E_{2}=\frac{Kq}{PO^{2}}=\frac{9\times 10^{9}\times 8\times 10^{-9}}{9}=8 N/C

According to the diagram, tanθ = 3/4

Resolve the components of E1 along x axis and along y axis.

So, Electric field along X axis, Ex = - E1 Cos θ

Ex = - 27 x 4 / 5 = - 21.6 N/C

Electric field along y axis, Ey = E1 Sinθ - E2

Ey = 27 x 3 /5 - 8 = 8.2 N/C

The resultant electric field at P is given by

E=\sqrt{E_{x}^{2}+E_{y}^{2}}=\sqrt{(-21.6)^{2}+(8.2)^{2}}=23.1 N/C

3 0
3 years ago
What is the area of the circle with a radius of 12.77m
Arada [10]
A=pi r^2
A=( 3.14159.......)(12.77)^2
A= 512.30m^2
8 0
3 years ago
If 2 people are on a bed and they are the same weight, and 1 of them gets off and the bed breaks who is responsible? Is it the p
alekssr [168]

Answer:

I would say the one who got up bc if he or she wouldn't have gotten up the bed wouldn't have broke

6 0
3 years ago
The light which allows you to see this very interesting exam is made up of waves. In these waves, the distance between crests is
lakkis [162]

Answer:

idk

Explanation:

idk

5 0
3 years ago
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