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ludmilkaskok [199]
2 years ago
14

How many joules of work are done on a box when a force of 25 N pushes it 3 m?

Physics
1 answer:
Anika [276]2 years ago
7 0

Answer:

75joules

Explanation:

Workdone = force x distance

workdone = 25 x 3

workdone = 75joules

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The correct equation for the x component of a vector named A with an angle measured from the x axis would be which of the follow
Lady_Fox [76]

Answer:

Acosθ

Explanation:

The x-component of a vector is defined as :

Magnitude * cosine of the angle

Maginitude * cosθ

The magnitude is represented as A

Hence, horizontal, x - component of the vector is :

Acosθ

Furthermore,

The y-component is taken as the sin of the of the angle multiplied by the magnitude

Vertical, y component : Asinθ

8 0
3 years ago
An unmarked police car traveling a constant 95 km/h is passed by a speeder. Precisely 1.00 s after the speeder passes, the polic
Montano1993 [528]

Answer:

Speed of the speeder will be 28 m/sec

Explanation:

In first case police car is traveling with a speed of 90 km/hr

We can change 90 km/hr in m/sec

So 90km/hr=\frac{90\times 1000m}{3600sec}=25m/sec

Car is traveling for 1 sec with a constant speed so distance traveled in 1 sec = 25×1 = 25 m

After that car is accelerating with a=2m/sec^2 for 7 sec

So distance traveled by car in these 7 sec

S=ut+\frac{1}{2}at^2=25\times 7+\frac{1}{2}\times 2\times 7^2=224m

So total distance traveled by police car = 224 m

This distance is also same for speeder

Now let speeder is moving with constant velocity v

so 224=\left ( 1+7 \right )v

v = 28 m/sec

4 0
3 years ago
Read 2 more answers
The engine of a 1520-kg automobile has a power rating of 75 kW. Determine the time required to accelerate this car from rest to
LUCKY_DIMON [66]

Answer:

t=15.68 s

Explanation:

Given that

m = 1520 kg

P =75 KW

We know that

Power  ,P = F .v

F=force

v=velocity

v= 100 km/h

v=\dfrac{1000}{3600}\times 100\ m/s

v=27.77 m/s

75 x 1000  = F x 27.77

F= \dfrac{75000}{27.77}\ N

F= 2700.75 N

F= m a

m=mass

a=acceleration

2700.75 = 1520 x a

 a=1.77 m/s²

time t given as

v= u + a t

27.77 = 0 + 1.77 x t

t=15.68 s

3 0
3 years ago
Chemical properties of an acid include...
Igoryamba
This is a list of well known characteristics of acids:

1) acids increase the concentration of hydronum ions ([H3O+]) when dissolved in water

2) acids taste sour

3) many are corrosive (the higher the acidity the higher the corrosive property)

4) when acids react with some metals produce hydrogen gas

5) acids conduct electricity (due to the presence of hydronium ions)

6) acids neutralize bases

7) acids combine with bases to produce water and salt

8) acids lower the pH of solutions.

They do not feel sticky to the touch. Bases fell slippery but there is not that property of sticky sensation about acids, although some highly concentrated strong acids have high viscosity. You cannot touch highly concentrated strong acids.


8 0
2 years ago
Read 2 more answers
A uniform 2.50m ladder of mass 7.30kg is leaning against a vertical wall while making an angle of 51.0degree with the floor. A w
Zigmanuir [339]

Answer:

19.95 J

Explanation:

The center of mass of the ladder is initially at a height of:

h_1=\frac{L}{2}sin\theta

The center of mass of the ladder ends at a height of:

h_2= \frac{L}{2}sin90 =L/2

So, the work done is equal to the change in potential energy which is:

W = PE = mg(h_2-h_1)

now h_2-h_1= 1-sin\theta

therefore

W = [mgL/2]×[1 - sin(theta)]

W = [(7.30)(9.81)(2.50)/2]×[1-sin(51°)]

solving this we get

W = 19.95 J

8 0
2 years ago
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