1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ira [324]
4 years ago
12

How many grams of water vapor (H2O) are in a 10.2-liter sample at 0.98 atmospheres and 26°C?

Chemistry
1 answer:
diamong [38]4 years ago
5 0
Hey there! 

<span>Use the equation of Clapeyron:
</span>
T in kelvin :

26 + 273.15 => 299.15 K

R = 0.082

V = 10.2 L

P = 0.98 atm

number of moles :

P *V = n * R * T

0.98 * 10.2 =  n * 0.082 * 299.15

9.996 = n * 24.5303

n = 9.996 / 24.5303

n = 0.4074 moles

Therefore:

Molar mass H2O = 18.01 g/mol

1 mole H2O ------------- 18.01 g
0.4074  moles ----------- m

m = 0.4074 * 18.01 / 1

m = 7.339 g of H2O
You might be interested in
Which of the following situations is most favorable for solubility? View Available Hint(s) Which of the following situations is
bixtya [17]

Answer:

strong attraction of solute particles to solvent particles

Explanation:

Solubility occurs when the solute-solvent attraction is more than the solute-solute and solvent-solvent interactions.

<u>A solute solubles in the solvent when the solute solute interactions and the solvent solvent interaction decreases and there is more strong interaction of the solute particles to the solvent particles. </u>

7 0
3 years ago
Read 2 more answers
A student prepares a 100.0 mL solution using 44.7 grams of potassium nitrite. They then take 11.9 mL of this solution and dilute
Naddik [55]

Answer:

0.52 g of KNO₃ are contained in 19.7 mL of diluted solution.

Explanation:

We can work on this problem in Molarity cause it is more easy.

Molarity (mol/L) → moles of solute in 1L of solution.

100 mL of solution = 0.1 L

We determine moles of solute: 44.7 g . 1mol /101.1 g = 0.442 mol of KNO₃

Our main solution is 0.442 mol /0.1L = 4.42 M

We dilute: 4.42 M . (11.9mL / 200mL) = 0.263 M

That's concentration for the diluted solution.

M can be also read as mmol/mmL, so let's find out the mmoles

0.263 M . 19.7mL = 5.18 mmol

We convert the mmol to mg → 5.18 mmol . 101.1 mg / mmol = 523.7 mg

Let's convert mg to g → 523.7 mg . 1 g / 1000 mg = 0.52 g

6 0
3 years ago
Lithium has the electron arrangement 2,1. When lithium forms an ion,
iragen [17]

Answer:

when lithium forms an ion it donates 1 electron

which makes its electron configuration to become 2

4 0
3 years ago
You are counting red blood cells, which objective will be best to count the number of cells, high power or low power objective a
BARSIC [14]

Answer:

Low power

Explanation:

Low power would allow for the full image of the red blood cells and would appear as small circles.

4 0
3 years ago
The conversion of 1 mole of water at 0°c to 1 mole of ice at 0°c releases 6.01 kj. what must be true about the heat absorbed dur
love history [14]
It must be 6.01 kj
................



6 0
3 years ago
Read 2 more answers
Other questions:
  • What type of reaction is hydrolysis
    11·1 answer
  • Which is a possible result of rising ocean temperatures caused by global warming?
    5·1 answer
  • Be sure to answer all parts. The thermal decomposition of phosphine (PH3) into phosphorus and molecular hydrogen is a first-orde
    9·1 answer
  • How do I solve this?
    15·1 answer
  • Mole fraction of the solute in a 1.00. What is the molal aqueous eqaution?
    10·1 answer
  • the coldest temperature ever recorded in Virginia was 3 degrees below zero how would you represent this temperature as an intege
    12·2 answers
  • What does the (lll) in iron ion mean
    9·1 answer
  • Calcium carbonate decomposes at high temperatures to give calcium oxide and carbon
    14·1 answer
  • 1.Calculate the mass of compound required to prepare 100.00 mL of a 1.40x10-2M CuCl2.Show your work.
    15·1 answer
  • Whats the answers 1-10 on brainpop nervous system i need help
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!