Answer:
Moles of water in 7.1×10²⁵ molecules are 118 mol.
Explanation:
Given data:
Number of molecules of water = 7.1×10²⁵ molecules
Moles of water in 7.1×10²⁵ molecules = ?
Solution;
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
1 mole = 6.022 × 10²³ molecules of water
7.1×10²⁵ molecules of water × 1 mol / 6.022 × 10²³ molecules of water
1.18×10² moles of water 0r 118 moles of water
Chemicals dissolved in water. Calcite is a good example, if I'm not mistaken.
1 mole of h3bo3...........6.023*10²³ each h and B and 0 so we will have 3hydrogen+ 1 B+3 oxygen = 7*6.023*10²³ atoms
1 mole .......7*6.023*10²³atoms
4 moles ........x atoms
x=4*7*6.023*10²³.
Answer:
The answer to your question is V2 = 66.7 ml
Explanation:
Data
Volume 1 = V1 = 400 ml
Pressure 1 = P1 = 1 atm
Volume 2 = V2 = ?
Pressure 2 = P2 = 6 atm
Process
1.- To solve this problem use Boyle's law
P1V1 = P2V2
-solve for V2
V2 = P1V1 / P2
-Substitution
V2 = (1)(400) / 6
-Simplification
V2 = 400 / 6
-Result
V2 = 66.7 ml
Answer:
<h3>... :-!...................nose...........</h3>
