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Ksenya-84 [330]
3 years ago
9

If an equation is dimensionally correct is thar equation a right equation​

Physics
1 answer:
Nady [450]3 years ago
8 0

If an equation is dimensionally correct, it does not mean that the equation must be true. On the other hand, when the equation is dimensionally correct, the equation cannot be true. Dimensional analysis is a technique used to check whether a relationship is correct

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A boxed 12.0 computer monitor is dragged by friction 7.50 up along the moving surface of a conveyor belt inclined at an angle of
sasho [114]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

Below is the solution:

W done by Normal = 0. (make the incline flat, Normal force goes directly up: no work done) 
<span>W done by gravity = w*displacement = (11kg*9.8) * 7.5sin(35) = -463J </span>
<span>W done by friction is the opposite of the work done by weight because the object is not moving. Therefore W done by friction = 463J</span>
8 0
3 years ago
A 3.0 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi
krok68 [10]

Answer:

a) k = 2231.40 N/m

b) v = 0.491 m/s

Explanation:

Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.

when the box encounters the spring, all the energy of the box is kinetic energy:

the energy relationship between the box and the spring is given by:

1/2(m)×(v^2) = 1/2(k)×(x^2)

    (m)×(v^2) = (k)×(x^2)

a) (m)×(v^2) = (k)×(x^2)

                 k = [(m)×(v^2)]/(x^2)

                 k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)

                 k = 2231.40 N/m

Therefore, the force spring constant is 2231.40 N/m

b) (m)×(v^2) = (k)×(x^2)

             v^2 = [(k)(x^2)]/m

                 v =  \sqrt{ [(k)(x^2)]/m}

                 v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}

                    = 0.491 m/s

8 0
3 years ago
Read 2 more answers
A student was walking with a mass of 40 kilograms and an acceleration of 1 m/s/s. What is the force exerted on her?
ValentinkaMS [17]

Answer:

B

Explanation:40x1=40       40=b

brainlyest plz

3 0
3 years ago
Which one is not physical quantity question is mistake
Anastaziya [24]

Answer:

Length

Explanation:

5 0
3 years ago
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A 34.1-mL sample of benzene at 20.8°C was cooled to its melting point, 5.5 °C, and then frozen at 5.5 °C. Calculate the quantity
posledela

Answer:

4541.8 J

Explanation:

First we find the mass of benzene available

mass = density x volume

         = 0.867 x 34.1

         = 29.5647 g

Then we find the amount of heat transferred by two processes:

heat tranferred = heat lost during temp drop + heat lost during freezing

                         = mcΔT + mL

                         = 29.5647 x 1.74 x (20.8 - 5.5) + 29.5647 x 127

                         = 4541.7883434 J

                         = 4541.8 J

                         

3 0
3 years ago
Read 2 more answers
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