Question

Pls help me with this question its due tomorrow and I can't find the answer: A person jumped 50cm, the hang time for the jump was 0.778 seconds, calculate a value for the acceleration due to gravity. What is the percent error in the value for acceleration you found? (Solve it without factoring in the air)

Answer 1

S = ut + 1/2gt²

where S = distance

50 cm = 0.5m

u is initial velocity = 0

S = 0*t + 1/2gt²

S = 1/2gt²

0.5 = 1/2 g (0.778²)

2*0.5 = g(0.778²)

1/(0.778²) = g

g = 1.65m/s²

The value of g is grossly errored due to the values obtained since the known value of g on earth is 9.8m/s² the obtained value rounds off to the value of g on moon.