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ira [324]
3 years ago
12

Pls help me with this question its due tomorrow and I can't find the answer: A person jumped 50cm, the hang time for the jump wa

s 0.778 seconds, calculate a value for the acceleration due to gravity. What is the percent error in the value for acceleration you found? (Solve it without factoring in the air)

Physics
1 answer:
son4ous [18]3 years ago
4 0

S = ut + 1/2gt²

where S = distance

50 cm = 0.5m

u is initial velocity = 0

S = 0*t + 1/2gt²

S = 1/2gt²

0.5 = 1/2 g (0.778²)

2*0.5 = g(0.778²)

1/(0.778²) = g

g = 1.65m/s²

The value of g is grossly errored due to the values obtained since the known value of g on earth is 9.8m/s² the obtained value rounds off to the value of g on moon.

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Charlie pulls horizontally to the right on a wagon with a force of 37.2 N. Sara pulls horizontally to the left with a force of 2
Sidana [21]

Answer:

The work done on the wagon is 37 joules.

Explanation:

Given that,

The force applied by Charlie to the right, F = 37.2 N

The force applied by Sara to the left, F' = 22.4 N

We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :

F_n=F-F'

F_n=37.2-22.4

F_n=14.8\ N

Work done on the wagon is given by the product of net force and displacement. It is given by :

W=F_n\times d

W=14.8\ N\times 2.5\ m

W = 37 Joules

So, the work done on the wagon is 37 joules. Hence, this is the required solution.

7 0
3 years ago
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Help! <br><br> I need to do this quickly!!!
umka2103 [35]
D is the answer. It is a firm statement.
8 0
2 years ago
Two identical masses are connected to two different flywheels that are initially stationary. Flywheel A is larger and has more m
inysia [295]

Answer:

a) True. There is dependence on the radius and moment of inertia, no data is given to calculate the moment of inertia

c) True. Information is missing to perform the calculation

Explanation:

Let's consider solving this exercise before seeing the final statements.

We use Newton's second law Rotational

      τ = I α

     T r = I α

     T gR = I α

     Alf = T R / I (1)

     T = α I / R

Now let's use Newton's second law in the mass that descends

     W- T = m a

     a = (m g -T) / m

The two accelerations need related

     a = R α

    α = a / R

    a = (m g - α I / R) / m

    R α = g - α I /m R

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    α = g / R (1 + I / mR²)

We can see that the angular acceleration depends on the radius and the moments of inertia of the steering wheels, the mass is constant

Let's review the claims

a) True. There is dependence on the radius and moment of inertia, no data is given to calculate the moment of inertia

b) False. Missing data for calculation

c) True. Information is missing to perform the calculation

d) False. There is a dependency if the radius and moment of inertia increases angular acceleration decreases

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3 years ago
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alexandr402 [8]
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zepelin [54]

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