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3 years ago

How do inertia and centripetal force combine to keep an object moving in circular motion?

2 answers:

6 0

As the centripetal force acts upon an object moving in a circle at constant speed, the force always acts inward as the velocity of the object is directed tangent to the circle. ... In fact, whenever the unbalanced centripetal force acts perpendicular to the direction of motion, the speed of the object will remain constant.

mash [69]3 years ago

5 0

Answer:

As we know that inertia it the property of mass which resist any change in the state of motion of the object. Which means object has tendency to move in its initial state of motion and when we try to change that state of motion then object will resist to change that.

While moving in circular path the object will have tendency to change it's direction of motion at each instant. So this change in the direction of motion at every instant is due to centripetal acceleration of the object.

Now when object is revolving in circular path then the inertia of the object will help to move the object in tangential direction at every moment of the motion while the centripetal acceleration of the object will have tendency to change the direction at each moment of the motion.

So here we will say that inertia and centripetal force combine to keep an object moving in circular motion

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A 40 kg bear slides, from rest, 14 m down a lodgepole pine tree, moving with a speed of 3.7 m/s just before hitting the ground.

antiseptic1488 [7]

Answer:

A. -5488J

B. 273.8J

C. 372.44N

Explanation:

Given:

m = 40kg

h = 14 m

v= 3.7 m/s

Part(a)

The change in the potential energy of the bear Earth system during the slide

AU = -mgh = -40(9.8) (14) = -5488 J

Part(b)

The kinetic energy of the bear just before hitting the ground is

Ks 1/2 mV^2= (40)(3.7)2 = 547.6 /2 = 273.8J

Part(c)

The change in the thermal energy of the system due to friction is

AEth = fxh=-(AK +AU) = 5488– 273.8 = 5214.2 J

The average frictional force that acts on the sliding bear is

F = Eth / 14= 5214.2/14 =372.44N

4 0

3 years ago

Read 2 more answers

Carbon-14 has a half life of 5730 years. Consider a sample of fossilized wood that when alive would have contained 24g of C-14 i

kirza4 [7]

Answer:

5732 years

Explanation:

hope it helps, if not im sorry

6 0

3 years ago

Write equations for both the electric and magnetic fields for an electromagnetic wave in the red part of the visible spectrum th

NeTakaya

Answer:

Explanation:

General equation of the electromagnetic wave:

$E(x, t)= E_0sin[\frac{2\pi}{\lambda}(x-ct)+\phi ]$

where

$\phi =$ Phase angle, 0

c = speed of the electromagnetic wave, 3 × 10⁸

$\lambda =$ wavelength of electromagnetic wave, 698 × 10⁻⁹m

E₀ = 3.5V/m

Electric field equation

$E(x, t)= 3.5sin[\frac{2\pi}{6.98\times10^{-7}}(x-3\times 10^8t)]\\\\E(x, t)= 3.5sin[{9 \times 10^6}(x-3\times 10^8t)]\\\\E(x, t)= 3.5sin[{9 \times 10^6x-2.7\times 10^{15}t)]$

Magnetic field Equation

$B(x, t)= B_0sin[\frac{2\pi}{\lambda}(x-ct)+\phi ]$

Where B₀= E₀/c

$B_0 = \frac{E_0}{c} = \frac{3.5}{3\times10^8}=1.2 \times 10^{-8}T$

$B(x, t)= 1.2\times10^{-8}sin[\frac{2\pi}{6.98\times10^{-7}}(x-3\times 10^8t)]\\\\B(x, t)= 1.2\times10^{-8}sin[{9 \times 10^6}(x-3\times 10^8t)]\\\\B(x, t)= 1.2\times10^{-8}sin[{9 \times 10^6x-2.7\times 10^{15}t)]$

6 0

3 years ago

The speed of light is 3.0 x 10^8 m/s. If the wavelength of a light wave is 5.8 x 10^-7 m, what is its frequency

ddd [48]

Answer:

The frequency is 517.24 THz

Explanation:

Given:

The speed of light = 3.0 x $10^{8}$ m/s

The wavelength of light wave = 5.8 x $10^{-7}$ m

Frequency = ?

We know that the relation among speed of light, wavelength and frequency is given by

c = νλ , where

c is speed of light

ν is the frequency

λ is the wavelength

To find the frequency(ν):

ν = c / λ

= $\frac{3.0 x 10^{8} ms^{-1} }{5.8 x 10^{-7}m }$

= $\frac{3}{5.8}$ x $10^{15}$

= (3000/5.8) x $10^{12}$

= 517.24 x $10^{12}$ $s^{-1}$

= 517.24 x $10^{12}$ Hz (since 1 $s^{-1}$ = 1 Hz)

= 517.24 THz (Tera Hertz)

Hence the frequency is 517.24 THz.

7 0

3 years ago

A sphere is charged with electrons to −9 × 10−6 C.

Rus_ich [418]

To refer to the original question?The answer is approxamately 24 electrons on a sphere.

But the answer to the problem is:1.6 x 10-19 
(-8x10-6)/(-1.6x10-19)=5x10^13

6 0

3 years ago