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3 years ago

How do inertia and centripetal force combine to keep an object moving in circular motion?

2 answers:

6 0

As the centripetal force acts upon an object moving in a circle at constant speed, the force always acts inward as the velocity of the object is directed tangent to the circle. ... In fact, whenever the unbalanced centripetal force acts perpendicular to the direction of motion, the speed of the object will remain constant.

mash [69]3 years ago

5 0

Answer:

As we know that inertia it the property of mass which resist any change in the state of motion of the object. Which means object has tendency to move in its initial state of motion and when we try to change that state of motion then object will resist to change that.

While moving in circular path the object will have tendency to change it's direction of motion at each instant. So this change in the direction of motion at every instant is due to centripetal acceleration of the object.

Now when object is revolving in circular path then the inertia of the object will help to move the object in tangential direction at every moment of the motion while the centripetal acceleration of the object will have tendency to change the direction at each moment of the motion.

So here we will say that inertia and centripetal force combine to keep an object moving in circular motion

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3 years ago

Which is the correct product of the significant figures 3278 and 42?

Svetradugi [14.3K]

Answer:

$1.4\cdot 10^5$

Explanation:

In multiplications or divisions, the result must be written using a number of significant figures equal to the smallest number of significant figures contained in the original numbers.

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So, the product must be written using 2 significant figures.

Calculating the product, we get:

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3 years ago

Future space stations will create an artificial gravity by rotating. Consider a cylindrical space station 100 m diameter rotatin

Zielflug [23.3K]

Given Information:

Diameter = d = 100 m

Required Information:

Period = T = ?

Answer:

Period = T = 14.2 seconds

Explanation:

We know that a station revolving at an angular velocity ω, have an acceleration given by

α = ω²r

Where ω is angular velocity and r is the radius of cylindrical space station.

Normal gravity means α = g = 9.8 m/s²

ω² = α/r

ω = √(α/r)

The radius is given by

r = d/2

r = 100/2

r = 50 m

ω = √(9.8/50)

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f = ω/2π

f = 0.4427/2π

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T = 1/f

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Therefore, the rotation period is 14.2 seconds.

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