Answer:
p2 = 9.8×10^4 Pa
Explanation:
Total pressure is constant and PT = P = 1/2×ρ×v^2
So p1 + 1/2×ρ×(v1)^2 = p2 + 1/2×ρ×(v2)^2
from continuity we have ρ×A1×v1 = ρ×A2×v2
v2 = v1×A1/A2
and
r2 = 2×r1
then:
A2 = 4×A1
so,
v2 = (v1)/4
then:
p2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v2)^2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v1/4)^2
p2 = 3.0×10^4 Pa + 1/2×(1000 kg/m^3)×(12m/s)^2 - 1/2×(1000kg/m^3)×(12^2/16)
= 9.75×10^4 Pa
= 9.8×10^4 Pa
Therefore, the pressure in the wider section is 9.8×10^4 Pa
Answer:
Net head = 380cm
bhp = 17.710kW
Explanation:
Angular velocity of centrifugal pump:
Normal velocity component at outlet of pump:
Tangential velocity component at exit of the pump:
Normal velocity component at inlet of pump:
Tangential velocity component at inlet of the pump:
Equivalent head in centimetre of water column:
Break horse power:
![bhp=rho_{water} gHV=rho_{water} g[(\frac{w}{g})(r_{2}V_{2,t}-r_{1}V_{1,t})]V\\\\bhp=(998)(9.81)[(\frac{78.54}{9.81})((0.24)(1.643)-(0.12)(0))](0.573)=17710W=17.710kW](https://tex.z-dn.net/?f=bhp%3Drho_%7Bwater%7D%20gHV%3Drho_%7Bwater%7D%20g%5B%28%5Cfrac%7Bw%7D%7Bg%7D%29%28r_%7B2%7DV_%7B2%2Ct%7D-r_%7B1%7DV_%7B1%2Ct%7D%29%5DV%5C%5C%5C%5Cbhp%3D%28998%29%289.81%29%5B%28%5Cfrac%7B78.54%7D%7B9.81%7D%29%28%280.24%29%281.643%29-%280.12%29%280%29%29%5D%280.573%29%3D17710W%3D17.710kW)
The force of gravity between Earth and Mars will decrease.
The gravitational law is given as-
F = G mM/r²
here, m= mass of rocket
M = mass of earth
r = distance between earth and rocket
So, as rocket takes off from earth and fly towards mars then the distance starts to increase between earth and rocket, and the gravitational pull between them starts to weaken. Then a point will reach when rocket will far from gravity of earth and could probably enter the gravity of Mars.
Learn more about gravitational law here:
brainly.com/question/12101547
#SPJ4
Answer:
Answer:
f) The puck conserves its original momentum but loses some, but not all, of its mechanical energy.
Explanation:
It is a case of perfectly inelastic collision . So momentum will be conserved because no external force acts on them during the collision . But there will be loss of energy ( kinetic energy ) . It will be in the form of sound or heat that is produced during collision. They will still have some kinetic energy even after the collision.
Explanation:
Answer to the question provided is A
