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Firdavs [7]
2 years ago
9

How do I determine the amount of time taken to empty a large tank full of water?

Physics
1 answer:
mr Goodwill [35]2 years ago
7 0

Answer:

The tank should be empty in about 2-1/4 hours. Variables: h = elevation of tank D = diameter of tank A = orifice area (ft2) G = gravitational acceleration = 32.2 ft/sec2 ∆t = time required to empty tank (sec) The following formulas are based on turbulent flow of a Newtonian fluid through an outlet (orifice) in a tank.Explanation:Measure the number of liters or gallons in the container, and divide that number by 15. This gives the flow rate in liters per second or gallons per second. The formula is F = V/T, where F is the flow rate, V is the volume and T is the time.=180 s=3 min.

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Yuliya22 [10]
I believe it would be c
5 0
3 years ago
A-delta fibers : A) are small, myelinated fibers. B) transmit pain signals at a slower rate than C-fibers. C) typically transmit
daser333 [38]

Answer:

A

Explanation:

Aδ fibers carry cold, pressure, and acute pain signals, and because they are thin (2 to 5 μm in diameter) and myelinated, they send impulses faster than unmyelinated C fibers, but more slowly than other, more thickly myelinated group A nerve fibers. Their conduction velocities are moderate.

7 0
2 years ago
A mountain climber weighs 42.0 N. If he climbs a hill 100m high. Calculate the work done in joules​
quester [9]

Answer:

The answer is 4200 J.

Explanation:

The formula of work done is, W = F×D where F is the force of an object and D is the distance. Then you just substitute the values into the equation :

W = F×D

F = 42N

D = 100m

W = 42 × 100

= 4200 J

5 0
2 years ago
A rope is tied to a box and used to pull the box 2.3 m along a horizontal floor. The rope makes an angle of 30∘ with the horizon
Savatey [412]

Answer:

Answered

Explanation:

A) The work done by gravity is zero because displacement and the gravitational force are perpendicular to each other.

W= FS cosθ

θ= 90 ⇒cos90 = 0 ⇒W= 0

B) work done by tension

W= Tcosθ×S= 5cos30×2.30= 10J

C) Work done by friction force

W= f×s=1×2.30= 2.30 J

D) Work done by normal force is Zero because the displacement and the normal force are perpendicular to each other.

E) The net work done= Work done by tension in the rope - frictional work

=10-2.30= 7.7 J

6 0
2 years ago
A car travels 45 km due north and 70 km west. What is the car's displacement? 6 points 24.7 km northeast 83.2 km northwest 76.5
HACTEHA [7]

Answer:

3150

Explanation:

if if you were two times 45 times 70 it would give you that answer

8 0
3 years ago
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