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uranmaximum [27]
3 years ago
11

Need Some Help Please :)

Physics
2 answers:
joja [24]3 years ago
6 0
1. The amount of energy carried by the wave is related to the Amplitude of the wave.
2. A mechanical wave requires an initial energy input, Once this initial energy is added the wave travels through the medium until all it's energy is transferred.
yanalaym [24]3 years ago
6 0

Answer:

  1. The higher the wave, the higher the frequency
  2. Energies are transferred in mechanical waves through a medium

Explanation:

<u>How frequency relates to the energy of the wave</u>

Literally, frequency of a wave refers to the number of waves that move past a certain point during a given amount of time, (although it is often measured per second )

So, this means that when more waves moves past the given points, the frequency of the wave will get increased and if other wise, the frequency if the wave will get reduced, this is so because wave frequency is related to wave energy.

Since all that waves really are is traveling energy, the more energy in a wave, the higher its frequency. The lower the frequency is, the less energy in the wave.

<u>How energy is transferred through mechanical wave</u>

Mechanical waves are such that they're not capable of transmitting energy via vacuum. Hence, they need a medium to transmit these energies from one point to another.

All type of mechanical waves need a form of medium in order to transmit.

Take for instance:

  • A slinky wave requires the coils of the slinky;
  • A water wave requires water

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30 POINTS!!! CAN U AWNSER IT?? :)
solniwko [45]

Answer:

5235.84 kg

Explanation:

There is one theorem - whose proof I will never remember without having to drag calculus in there - that says that the variation of momentum is equal to the force applied times the time the application last.

F\Delta t = m \Delta v As long as the engine isn't ejecting mass - at this point it's a whole new can of worm - we know the force, we know the variation in speed, time to find the mass. But first, let's convert the variation of speed in meters per second. The ship gains 250 kmh, \Delta v = 69.4 m/s;

45 450 \cdot 8 = 69.4 m \rightarrow m = \frac{45450\cdot 8}{69.4} = 5235.84 kg

7 0
3 years ago
Please help me to do this problem
Novosadov [1.4K]

Answer:

we got time and velocity over time.

so the distance is again the area underneath the graph

for a triangle with known base and height it's

4*10 / 2

distance traveled is 20

deceleration occurs when velocity decreases. that happens from t=2 till t=4

in 2 time-units we loose 10 units of velocity, so we decelerate by 5 units per 1 time

a (from t=2 to t=4) = -5v/t

7 0
3 years ago
Which type of rock can only form below earths surface?
Inessa [10]

Answer: Igneous it forms because of magma but magma is under the earths surface so its Igneous

Explanation:

7 0
2 years ago
Read 2 more answers
How can a volcano develop in the middle of a tectonic plate?
Sunny_sXe [5.5K]

Answer:

Volcanoes that form away from plate boundaries are created by hotspots. A hotspot is an area in the mantle that is believed to be somewhat hotter than the surrounding material. The rising magma from the hotspot can push its way through the crust and burst out at the surface, forming a volcano.

Explanation:

6 0
3 years ago
the speed of travel of the moon around the earth, using the formula for the speed of a moving object in a circular path
Svetach [21]

Answer: 1018.26 m/s

Explanation:

Approaching the orbit of the Moon around the Earth to a circular orbit (or circular path), we can use the equation of the speed of an object with uniform circular motion:  

V=\sqrt{G\frac{M}{r}}

Where:  

V is the speed of travel of the Moon around the Earth

G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}} is the Gravitational Constant

M=5.972(10)^{24} kg is the mass of the Earth

r=384400(10)^{3} m is the distance from the center of the Earth to the center of the Moon

Solving:

V=\sqrt{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{5.972(10)^{24} kg}{384400(10)^{3} m}}

V=1018.26 m/s This is the speed of travel of the Moon around the Earth

5 0
3 years ago
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