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3 years ago

According to newton's third law of motion, when a hammer strikes and exerts force to push it into a piece of wood, the nail

2 answers:

6 0

According to newton's third law of motion, when a hammer strikes and exerts force to push it into a piece of wood, the nail C. exerts an equal or opposite force on the hammer. The third law of motion states that every action has an equal BUT opposite reaction. This means that the nail exerts the same force the hammer exerts on it.

Kazeer [188]3 years ago

4 0

Answer:

Explanation:

because the energy is transfered

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A sample of a diatomic ideal gas has pressure P and volume V. When the gas is warmed, its pressure triples and its volume double

Andreyy89

Answer:

Amount of Energy transferred $=8.5PV$

Explanation:

Given:

Initial volume=V

Initial pressure=P

Final volume=2V

Final pressure=3P

Now w know that the Energy transferred in constant pressure pressure is given by

$E_1=nc_pdT\\\\E_1=n\times\dfrac{7R}{2}dT\\E_1=3.5(nRdT)\\E_1=3.5(V(2P-P))\\E_1=3.5PV$

Now the Energy transferred in constant volume process is given by

$E_2=nc_vdT\\\\E_2=n\times\dfrac{5R}{2}dT\\E_1=2.5(nRdT)\\E_1=2.5(V(3V-V))\\E_1=5PV$

The total Energy transferred is given by

$E_{total}=E_1+E_2\\E{total}=3.5PV+5PV\\=8.5PV$

3 0

2 years ago

Read 2 more answers

An electric drill operating at 120 volts draws a current of 3 Amperes. What is the total amount of electrical energy used by the

Liono4ka [1.6K]

<h3>Answer;</h3>

= 21600 Joules or 21.6 Kilo joules

<h3>Explanation;</h3>

Electrical energy is given by the formula = VIt ;

where V is the voltage in volts, I is the current in Amperes, and t is time in seconds.

Voltage = 120 volts

Current = 3 amperes

Time = 60 seconds or 1 minute

Therefore;

Electrical energy = 120 × 3 × 60

 = 21600 Joules or 21.6 Kilo joules

4 0

3 years ago

parallel-plate capacitor is made of two square plates 25 cm on a side and 1.0 mmapart. The capacitor is connected to a 50.0-V ba

noname [10]

Answer:

6.9 x 10^-7 J

3.5 x 10^-7 J

Explanation:

Identify the unknown:

The energies stored in the capacitor before and after the plates are pulled farther apart

List the Knowns:

Voltage of the battery: V = 50 V

Area of the plates: A = 0.25 x 0.25 = 0.0625 m^2

Original distance between the plates: d = 1 mm = 10^-3 m

New distance between the plates: d = 2 mm = 2 x 10^-3 m

Permittivity of free space: ∈o = 8.85 x 10^-12 C^2/Nm^2-

Set Up the Problem:

Capacitance of a parallel-plate capacitor:

C=∈o*A/d

Energy stored in a capacitor:

U_c=(1/2)*V^2*C

Solve the Problem:

Before the plates are pulled farther apart:

C = 8.85 x 10^-12 x 0.0625/10^-3 = 5•53 x 10^-10 F

U_c = (1/2) x (50)^2 x 5.53 x 10^-10= 6.9 x 10^-7 J

After the plates are pulled farther apart:

C = 8.85 x 10^-12 x 0.0625/2*10^-3 = 2•77 x 10^-10 F

U_c = (1/2) x (50)^2 x 2•77 x 10^-10 = 3.5 x 10^-7 J

The energy decrease because the capacitance decrease, so the stored charge decrease and transferred to the battery

3 0

3 years ago

If a car travels 30 miles in 5 hours, how many miles per hour is the car traveling?

Ivenika [448]

Answer:

6 mph

Explanation:

30 miles/5 hours = 6 mph

3 0

2 years ago

To determine the speed of a wave, you would use which of the following formulas?

vovangra [49]

Speed = wavelength x frequency determine the speed of a wave,

4 0

2 years ago

Read 2 more answers