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2 years ago

A plane’s average speed is 600 km/hr. If the trip takes 2.5 hours how far does a plane fly?

Physics

1 answer:

AnnyKZ [126]2 years ago

5 0

Answer:

1500 km

Explanation:

600x2.5=1500 (couldn't explain swear filter was for some reason saying I was swearing.) Hope it helps.

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When a cold air mass and a warm air mass meet but are at a standstill, the boundary is called.

Sphinxa [80]

Answer:

Ur answer is Stationary Front

Explanation:

Stationary Front is when a cold air mass and a warm air mass but are at a standstill the boundary is called Stationary Front.

3 0

2 years ago

GIVING BRAINIEST TO FAST ANSWER!!!!

Vlad [161]

Answer:

The second one a part of it heats up Earth's land and water equally.

Explanation:

Hope this help!!!

4 0

2 years ago

Read 2 more answers

An object is placed in front of a diverging lens, such that the object-to-image distance is 71 cm.

Pachacha [2.7K]

Explanation:

Given that,

Object-to-image distance d= 71 cm

Image distance = 26 cm

We need to calculate the object distance

$u -v= d$

$u=71+26=97\ cm$

We need to calculate the focal length

Using formula of lens

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

put the value into the formula

$\dfrac{1}{f}=\dfrac{1}{-26}+\dfrac{1}{97}$

$\dfrac{1}{f}=-\dfrac{71}{2522}$

$f=-35.52\ cm$

The focal length of the lens is 35.52.

(B). Given that,

Object distance = 95 cm

Focal length = 29 cm

We need to calculate the distance of the image

Using formula of lens

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

Put the value in to the formula

$\dfrac{1}{-29}=\dfrac{1}{v}-\dfrac{1}{95}$

$\dfrac{1}{v}=\dfrac{1}{-29}-\dfrac{1}{95}$

$\dfrac{1}{v}=-\dfrac{124}{2755}$

$v=-22.21\ cm$

We need to calculate the magnification

Using formula of magnification

$m=\dfrac{v}{u}$

$m=\dfrac{22.21}{95}$

$m=0.233$

The magnification is 0.233.

The image is virtual.

Hence, This is the required solution.

4 0

3 years ago

The capacitance of A conductor is affected by the presence of A second conductor that is uncharged and isolated electrically. Wh

Komok [63]

What happens is the potential value of the conductor decreases due to the presence of second conductor
as the capacitance is given by C = q/v
the value of v deceases as v-v1
thus the new capacitance is = C' = q/v-v1 thus the lowering of v increases the capacitance

5 0

3 years ago

if a sports car can go from 0 to 60 mph in 3.8 seconds, what would be it's final speed after 6 seconds if it's starting speed wa

erma4kov [3.2K]

Verrrrrry interesting !

Acceleration = (change in speed) / (time for the change)

The car's acceleration is (60 mph) / (3.8 sec) = (60/3.8) mile/hr-sec .

Final speed = (original speed) + (acceleration · time)

   = (30 mi/hr) + (60/3.8 mi/hr-sec)·(6 sec)

   = (30)mi/hr + (360 / 3.8)mi/hr

   = 124.7 mph .

4 0

3 years ago