<u>Answer:</u> 72 grams of water will be produced.
<u>Explanation:</u>
To calculate the number of moles, we use the formula:
....(1)
Mass of propane = 44 grams
Molar mass of propane = 44 grams
Putting values in above equation, we get:
![\text{moles of propane}=\frac{44g}{44g/mol}=1mole](https://tex.z-dn.net/?f=%5Ctext%7Bmoles%20of%20propane%7D%3D%5Cfrac%7B44g%7D%7B44g%2Fmol%7D%3D1mole)
For the reaction of combustion reaction of propane, the equation follows:
![C_3H_8+5O_2\rightarrow 3CO_2+4H_2O](https://tex.z-dn.net/?f=C_3H_8%2B5O_2%5Crightarrow%203CO_2%2B4H_2O)
By Stoichiometry of the reaction,
1 mole of propane produces 4 moles of water.
So, 1 mole of propane will produce =
of water.
Now, to calculate the amount of water, we use equation 1, we get:
Molar mass of water = 18 g/mol
![4mol=\frac{\text{Mass of water}}{18g/mol}](https://tex.z-dn.net/?f=4mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20water%7D%7D%7B18g%2Fmol%7D)
Mass of water produced = 72 grams
Hence, 72 grams of water will be produced.