Answer:
E = 29.7× 10⁻²⁰ j
Explanation:
Given data;
Frequency of light = 4.48 × 10¹⁴ Hz
Energy of photon = ?
Solution:
Formula:
E = h.f
E = energy of photon
h = planck's constant
f = frequency
E = h.f
E = 6.63 × 10⁻³⁴ Kg.m² /s × 4.48 × 10¹⁴ s⁻¹
E = 29.7× 10⁻²⁰ Kg.m²/s²
Kg.m²/s² = j
E = 29.7× 10⁻²⁰ j
This is because the relative atomic mass is the sum of the no of protons and neutrons while the atomic no is of the former only. it is not a whole number it is th average weighted masses of the various isotopes of the element multiplied by their corresponding relative abundance. pls thank me and mark me briniest
1.50x10^6 m2 is the answer you're looking for
Answer:
Option D.
Explanation:
Some of the alpha particles Rutherford shot at the gold foil bounced back, some scattered; but the majority of them went right through. That meant there had to be some sort of positively charged subatomic particle in there that pulled them through, but it had to be at the center and couldn't take up a lot of room.
Answer : The value of 
is -49.6 kJ/mol
Explanation :
First we have to calculate the reaction quotient.
Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.
The given balanced chemical reaction is,
The expression for reaction quotient will be :
![Q=\frac{[ADP][HPO_4^{2-}]}{[ATP]}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BADP%5D%5BHPO_4%5E%7B2-%7D%5D%7D%7B%5BATP%5D%7D)
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.
Given:
![[ATP]](https://tex.z-dn.net/?f=%5BATP%5D)
= 5.0 mM
![[ADP]](https://tex.z-dn.net/?f=%5BADP%5D)
= 0.60 mM
![[HPO_4^{2-}]](https://tex.z-dn.net/?f=%5BHPO_4%5E%7B2-%7D%5D)
= 5.0 mM
Now put all the given values in this expression, we get
Now we have to calculate the value of .
The formula used for is:
............(1)
where,
= Gibbs free energy for the reaction = ?
= standard Gibbs free energy = -30.5 kJ/mol
R = gas constant = 
T = temperature = 
Q = reaction quotient = 
Now put all the given values in the above formula 1, we get:
Therefore, the value of is -49.6 kJ/mol
