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nikdorinn [45]
3 years ago
12

A scientist should not let their research and study be influenced by _____. (can be more than one answer) ethnicity gender natio

nality religion
Chemistry
2 answers:
NikAS [45]3 years ago
8 0
I am going to say Race.
muminat3 years ago
7 0
The answer is all of the above
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Why do we need a “mole”?
Ivan
Wdym mole like the animal or something else ?
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2 years ago
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If 5,800 j of energy are applied to a 15.2 kg piece of lead, by how much does the temp change if the specific heat of lead is 0.
scoray [572]

Answer:

The answer will be 2.98K

Explanation:

Using the formula:

Q = mc∆T

Q= 5,800 (heat in joules)

m= convert 15.2kg to g which is 15200g (mass in grams)

c= 0.128 J/g °c (Specific heat capacity)

∆T=  what we need to find (temperature change)

5800J = 15200g x 0.128 x ∆T

= 2.98K  

7 0
3 years ago
Which gas will effuse at the rate closest At a particular pressure and temperature, nitrogen gas effuses at the rate of 79mLs. U
Contact [7]

Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of nitrogen gas = 79mL/s

R_2 = rate of effusion of sulfur dioxide gas = ?

M_1 = molar mass of nitrogen gas  = 28 g/mole

M_2 = molar mass of sulfur dioxide gas = 64 g/mole

Now put all the given values in the above formula 1, we get:

(\frac{79mL/s}{R_2})=\sqrt{\frac{64g/mole}{28g/mole}}

R_2=52mL/s

Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.

4 0
2 years ago
The reaction of nitrogen with methane in excess oxygen produces water, ________, and ___________. N2(g) + O2(g) + CH4(g) → CO2(g
IrinaVladis [17]

Answer:

C.

Explanation:

3 0
2 years ago
What is the mass of butane gas, C4H10, that can be held in a 3.00 L container at STP?
Lady bird [3.3K]

Answer:

3/22.4

Explanation:

8 0
2 years ago
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