Answer:
47.47 g of CO₂ is the amount formed.
Explanation:
The reaction is:
2C₆H₅COOH(aq) + 15O₂(g) → 14CO₂(g) + 6H₂O(l)
Let's apply the formula for the percent yield
Percent yield of reaction = (Produced yield/Theoretical yield) . 100
First of all we convert the moles of CO₂ to mass: 1.30 mol . 44 g /1 mol = 57.2 g. So now, we replace:
(Produced yield / 57.2 g ). 100 = 83
Produced yield / 57.2 g = 83 / 100
Produced yield / 57.2 g = 0.83
Produced yield = 0.83 . 57.2g → 47.47 g of CO₂
Answer:
D). Much lower than
Explanation:
When a ketone and its enol are in equilibrium, under most conditions the concentration of the enol is <u>Much lower than</u> the concentration of the ketone
because :
Carbon- oxygen bond is more stable(stronger) than Carbon-Carbon Bond
Keto - enol tautomerism is :
Ketone has C=O and enol has C=C
C=O bond energy is 745 kJ/mol
C=C bond energy is 614 kJ/mol
Yes i think so :) hope this helped
Answer:
A Glucose C6H12O6 is a covalent compound while NaCl sodium chloride is a ionic compound.
B Stronger molecular forces are present in NaCl because ionic bond is stronger than covalent bond.
C melting point allow us to predict the strength of intermolecular forces
High melting point stronger molecular forces and vice versa.
Explanation:
Explanation:
Never smoke near a place where hydrogen is generated or being used. Remove all possible sources of flame and sparks. Hydrogen should only be generated and used in a well ventilated out door area. Precautions must be taken to remove all possibilities of fire or explosion.
