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3 years ago

Which of the following is true about an abiotic resource?

Chemistry

1 answer:

aev [14]3 years ago

5 0

Answer:

B. It is a nonliving resource.

Explanation:

The definition of abiotic is "nonliving," and examples of abiotic resources may include soil or water.

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An unknown compound contains only C, H, and O. Combustion of 8.50 g of this compound produced 20.0 g CO2 and 5.46 g H2O. What is

Galina-37 [17]

Answer:

The answer to your question is: C₃H₄O

Explanation:

Data

CxHyOz = 8.5 g

CO2 = 20 g

H2O = 5.46 g

Reaction

CxHyOz + O2 ⇒ CO2 + H2O

CO2

MW = 44g

44g CO2 ----------------- 12g of C

20g CO2 ---------------- x

x = (20 x 12) / 44

x = 5.45 g of C

# of moles = n = 5.45 / 12 = 0.454 mol of C

H2O

MW = 18 g

18 g H2O ------------------- 2g of H

5.46 g -------------------- x

x = (5.46 x 2) / 18 = 0.61 g of H

n = 0.61 / 1 = 0.61 moles of H2

Mass of O2

mass CxHyOz = mass CO2 + mass H2 + mass O2

mass O2 = 8.5 - 5.45 - 0.61

mass O2 = 2.44g

n = 2.44 / 16 = 0.153 mol of O2

Now, divide by the lowest number of moles

0.454 mol of C/ 0.153 = 2.97 ≈ 3

0.61 moles of H2/ 0.153 = 3.99 ≈ 4

0.153 mol of O2/ 0.153 = 1

Then, the empirical formula is: C₃H₄O

7 0

3 years ago

What is the balanced form of the chemical equation shown below?

Serga [27]

Answer:

A; $1 C_{12}H_{22}O_{11} + 12 O_{2} - > 11H_2O +12CO_2$

Explanation:

The best way to start solving this problem is to start with the molecule with the most atoms. Since there are 12 carbons on the left, you need 12 on the right so 12 would need to be placed in front of carbon dioxide. Also you need 22 hydrogens and in each molecule of water, there are two hydrogen molecules so you need 11 molecules of water. After balancing you find that you need 24 oxygen on the left so you place the coeffecient 12 in front of the oxygen molecule.

4 0

2 years ago

It took 4.5 minutes for 1.0 l helium to effuse through a porous barrier. how long will it take for 1.0 l cl2 gas to effuse under

serious [3.7K]

When The rate of effusion is inversely proportional to the √molar mass of the substance.
and we have R(He) = 1L / 4.5 min so,
R(He)/R(Cl2) = (molar mass of Cl2/ molar mass of He)^0.5
and when we have the molar mass of Cl2 = 70.9 & the molar mass of He = 4
so by substitution:
(1L/4.5 min)/ R(Cl2) = (70.9 / 4)^0.5
(1L/4.5 min) / R(Cl2) = 4.21
∴R(Cl2) = (1L/4.5 min) / 4.21 = 1L/ (4.5*4.21)min = 1 L / 18.945 min
∴Cl2 will take 18.945 min for 1 L to effuse under identical conditions

4 0

4 years ago

What volume will 3.0 moles of O2 gas occupy at S.T.P?

REY [17]

Answer:

3 moles of oxygen at STP will occupy a volume of 3×22. 4=67. 2 L.

Explanation:

6 0

2 years ago

HELP!

katovenus [111]

Answer:

116.88 g

Explanation:

Step 1: Write the balanced equation for the synthesis of NaCl

Na + 1/2 Cl₂ ⇒ NaCl

Step 2: Calculate the moles corresponding to 45.978 g of Na

The molar mass of Na is 22.990 g/mol.

45.978 g × 1 mol/22.990 g = 1.9999 mol

Step 3: Calculate the number of moles of NaCl formed from 1.9999 moles of Na

The molar ratio of Na to NaCl is 1:1. The moles of NaCl formed are 1/1 × 1.9999 mol = 1.9999 mol.

Step 4: Calculate the mass corresponding to 1.9999 moles of NaCl

The molar mass of NaCl is 58.443 g/mol.

1.9999 mol × 58.443 g/mol = 116.88 g

3 0

3 years ago