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algol [13]
3 years ago
5

1. Ionization energy is the energy needed to remove an electron from an atom. We can use the periodic table to predict ionizatio

n energy for an element.
• State and explain the trend for ionization energy as you move from left to right across a period.


• State and explain the trend for ionization energy as you move down a group.


(5 points)
2. A neutral atom of phosphorus has 15 electrons. Explain why the electron configuration below is not the correct configuration for a neutral atom of phosphorus in its ground state.
1s2 2s2 2p6 3s2 3p2 4s1

3. Find rubidium, magnesium, and aluminum on the periodic table. Fill in the table below based on the locations of these metals on the periodic table. Be thorough in filling in the far right column!
left to right column: Element Symbol Group number Number of valence electrons General reactivity of the metal with an explanation for this reactivity based on the number of valence electrons
Up to down column:
Rubidium
Magnesium
Aluminum
Chemistry
1 answer:
just olya [345]3 years ago
6 0

Ionization energy increases from left to right because the left wants to lose elctrons and the right wants to gain electron

As you go a group it is easier lose lose because the electrons are farther away from the nucleus and there is less attraction from the positive charges.

It should be 3p3. the p level can hold 6 electrons

Rubidium group 1, 1 valence electrons very reactive

Mg2,2 very reactive

Al 3, 3 reactive


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Elenna [48]

The correct answer is D. chemical reaction.

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If the reduction reaction has a reduction potential of 0.1 V, and the oxidation reaction has a reduction potential of -0.4V, and
aleksley [76]

Answer : The value of ΔG expressed in terms of F is, -1 F

Explanation :

First we have to calculate the standard electrode potential of the cell.

E^o=E^o_{cathode}-E^o_{anode}

or,

E^o=E^o_{reduction}-E^o_{oxidation}

E^o=(0.1V)-(-0.4V)=+0.5V

Now we have to calculate the standard cell potential.

Formula used :

\Delta G^o=-nFE^o

where,

\Delta G^o = Gibbs free energy = ?

n = number of electrons = 2

F = Faraday constant

E^o = standard e.m.f of cell = +0.5 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times F\times 0.5)

\Delta G^o=-1F

Therefore, the value of ΔG expressed in terms of F is, -1 F

5 0
3 years ago
g For the following reaction, 0.500 moles of silver nitrate are mixed with 0.285 moles of copper(II) chloride. What is the formu
scZoUnD [109]

Answer:

CuCl_2 is the formula for the limiting reagent.

Mass of silver chloride produced is 71.8 g.

Explanation:

CuCl_2+2AgNO_3\rightarrow 2AgCl+Cu(NO_3)_2

Moles of silver nitrate = 0.500 mol

Moles of copper(II) chloride = 0.285 mol

According to reaction, 2 moles of silver nitrate reacts with 1 mole of copper chloride , then 0.500 mole of silver nitrate will react with :

\frac{1}{2}\times 0.500 mol=0.250 mol of copper(II) chloride

As we can see that moles of copper(II) chloride will be reacting is 0.250 mol less than present moles of copper (II) chloride ,so this means that silver nitrate is limiting reagent.

And moles of silver chloride to be formed will depend upon silver nitrate.

According to reaction, 2 moles of silver nitrate gives 2 moles of silver chloride , then 0.500 mole of silver nitrate will give  :

\frac{2}{2}\times 0.500 mol=0.500 mol of silver chloride

Mass of silver chloride produced:

0.500 mol × 143.5 g/mol = 71.8 g

7 0
3 years ago
The ion [Co(NH3)6]2+
Romashka-Z-Leto [24]

Explanation:

The answer would be  B.

As paramagnetic with 3 unpaired electrons. Since there are 6 ligands around the Co+2 ion it isoctahedral and these ligands are neutral. This makes the overall charge on the complex +2 and therefore comes from the configuration for Co+2 which is [Ar] 3d7. Since it is in high spin you must fill all the orbitals with at least one electron and then pair up any that remain. If you do this, 3 unpaired electrons remain. Para magnetism occurs in substances with unpaired electrons.

3 0
3 years ago
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