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algol [13]
3 years ago
5

1. Ionization energy is the energy needed to remove an electron from an atom. We can use the periodic table to predict ionizatio

n energy for an element.
• State and explain the trend for ionization energy as you move from left to right across a period.


• State and explain the trend for ionization energy as you move down a group.


(5 points)
2. A neutral atom of phosphorus has 15 electrons. Explain why the electron configuration below is not the correct configuration for a neutral atom of phosphorus in its ground state.
1s2 2s2 2p6 3s2 3p2 4s1

3. Find rubidium, magnesium, and aluminum on the periodic table. Fill in the table below based on the locations of these metals on the periodic table. Be thorough in filling in the far right column!
left to right column: Element Symbol Group number Number of valence electrons General reactivity of the metal with an explanation for this reactivity based on the number of valence electrons
Up to down column:
Rubidium
Magnesium
Aluminum
Chemistry
1 answer:
just olya [345]3 years ago
6 0

Ionization energy increases from left to right because the left wants to lose elctrons and the right wants to gain electron

As you go a group it is easier lose lose because the electrons are farther away from the nucleus and there is less attraction from the positive charges.

It should be 3p3. the p level can hold 6 electrons

Rubidium group 1, 1 valence electrons very reactive

Mg2,2 very reactive

Al 3, 3 reactive


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Answer:

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Explanation:

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What the the compound formula of Fe2+ + N3- ?
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5

Explanation:

8 0
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Ammonia, NH3NH3 , can react with oxygen to form nitrogen gas and water. 4NH3(aq)+3O2(g)⟶2N2(g)+6H2O(l) 4NH3(aq)+3O2(g)⟶2N2(g)+6H
solmaris [256]

Answer:

36.37% is the percent yield of the reaction.

Explanation:

4NH_3(aq)+3O_2(g)\rightarrow 2N_2(g)+6H_2O(l)

1)0.650 L nitrogen gas  , at 295 K and 1.01 bar.

Let the moles of nitrogen gas be n.

Pressure of the gas ,P=  1.01 bar = 0.9967 atm (1 bar = 0.9869 atm)

Temperature of the gas = T =  295 K

Volume of the gas = V = 0.650 L

Using an ideal gas equation:

PV=nRT

n=\frac{PV}{RT}=\frac{0.9967 atm\times 0.650 L}{0.0821 atm L/mol K\times 295 K}=0.0267 mol

2) Moles of ammonia gas=\frac{2.53 g}{17 g/mol}=0.1488 mol

Moles of oxygen gas =\frac{3.53 g}{32 g/mol}=0.1101 mol

According to reaction ,3 mol of oxygen reacts with 4 mol of ammonia.

Then,0.1101 mol of oxygen will react with:

\frac{4}{3}\times 0.1101 mol=0.1468 mol of ammonia.

Hence, oxygen gas is in limiting amount and act as limiting reagent.

3) Theoretical yield of nitrogen gas :

According to reaction, 3 mol of oxygen gas gives 2 moles of nitrogen gas.

Then 0.1101 mol of oxygen will give:

\frac{2}{3}\times 0.1101 mol=0.0734 mol of nitrogen.

Theoretical yield of nitrogen gas = 0.0734 mol

Experimental yield of nitrogen as calculated in part (1) = 0.0267 mol

Percentage yield:

\frac{\text{Experiential yield}}{\text{Theoretical yield}}\times 100

Percentage yield of the reaction:

\frac{ 0.0267 mol}{0.0734 mol}\times 100=36.37\%

36.37% is the percent yield of the reaction.

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What is the name of the compound with the formula PbF2?
Ber [7]

Lead fluoride hope this helps

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