Ask question

Ask question

All categories

3 years ago

12

Given the potential on a spherical shell of radius R to be V (R, θ) = V0 cos θ, calculate V (r, θ) both inside and outside the s

hell. From your result, determine the normal component of the electric field on either side of the shell, E+, and E−, and from them the charge on the shell σ(θ) = 0(E+ − E−). What is the total charge on the shell?

1 answer:

avanturin [10]3 years ago

5 0

Answer:

not sure

Explanation:

You might be interested in

What is the wavelenght and the frequencen of walkie-talkie?

GuDViN [60]

Nowadays, most of the walkie talkies ... and all R/C models ... operate in the "Family Radio Service" (FRS) band. That's 46-49 MHz. The wavelength is 6.12-6.52 meters.

8 0

3 years ago

The initial kinetic energy imparted to a 0.020 kg bullet is 1200 J. (a) Assuming it

Lilit [14]

Answer:

(a) Power= 207.97 kW

(b) Range= 5768.6 meter

Explanation:

Given,

Mass of bullet, $m=0.02 kg$

Kinetic energy imparted, $K=1200 J$

Length of rifle barrel, $d=1 m$

(a)

Let the speed of bullet when it leaves the barrel is $v$ .

Kinetic energy, $K=\frac{1}{2} mv^{2}$

$v=\sqrt{\frac{2K}{m} }$

$=\sqrt{\frac{2\times1200}{0.02} }$

$=346.4m/s$

Initial speed of bullet, $u=0$

The average speed in the barrel, $v_a_v_g=\frac{u+v}{2}$

$=\frac{0+346.4}{2} \\=173.2 m/s$

Time taken by bullet to cross the barrel, $t=\frac{d}{v}$

$=\frac{1}{173.2}\\ =0.00577 second$

Power, $P_a_v_g=\frac{W}{t}$

$=\frac{1200}{0.00577} \\=207.97kW$

(b)

In projectile motion,

Maximum height, $H_m=\frac{v^2\sin^2\theta}{2g} \\$

Range, $R=\frac{v^2\sin2\theta}{g}$

given that, $H_m=R$

then, $\frac{v^2\sin^2\theta}{2g}=\frac{v^2\sin2\theta}{g}\\\sin^2\theta=2\sin\theta\cos\theta\\\\\tan\theta=4\\\theta=\tan^-^14\\\theta=75.96^0\\R=\frac{v^2\sin2\theta}{g}\\=\frac{346.4^2\times\sin(2\times75.96)}{9.8}\\5768.6 meter$

5 0

3 years ago

Psychology only focus on how people think and feel. <br> True or false?

Shkiper50 [21]

It is false they focus on far more important things also.

6 0

3 years ago

Read 2 more answers

7 Consider two homogeneous bodies of

kupik [55]

Answer:

No, it is not necessary for them to have same mass.

Explanation:

Let both bodies have a density d1 and d2 respectively.

Since their volumes are equal V1 = V2

we know that,

density = $\frac{mass}{volume}$

Hence, d1 = $\frac{m1}{V1}$ and d2 = $\frac{m2}{V2}$

Taking the ratio of densities,we get

$\frac{d1}{d2} = \frac{m1}{m2}$

This implies that unless the bodies have same densities, the mass of the two bodies will not be same.

3 0

3 years ago

The drawing represents a mountain bike trail. A rider began at Point 1 on the trail and stopped at Point 3. At which point did h

Citrus2011 [14]

Answer:

Point 2.

Explanation:

Potential energy is simply defined as the energy stored in an object due to its position. It is can be represented mathematically by:

P.E = mgh

Where:

P.E is the potential energy.

m is the mass of the object.

g is acceleration due to gravity.

h is the height to which the object is located.

From the above equation, we can thus say that potential energy depends on the height of the object since the mass of the object is always constant i.e as the height of the object increase, the potential energy also increases and as the height of the object decrease, the potential energy also decreases.

Now, considering the diagram in the question given, we can see that point 2 is the lowest height to which the rider is located. At this point i.e point 2, the rider will have the least potential energy.

5 0

3 years ago