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3 years ago

9

A ball hangs on a string. The force of tension (Ft) in the string is 15n. The force due to gravity (Fg) pulls the ball down with

a force of 15 N. Show your work.

1 answer:

Tanya [424]3 years ago

7 0

Answer: 0N

Explanation: 15N-15N =0N

they are a balanced force,meaning they canceled each other out.

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The range of audible frequencies is from about 20.0 hz to 2.00×104 hz . what is range of the wavelengths of audible sound in air

TiliK225 [7]

The wavelength is related to the frequency by the relationship:
$\lambda= \frac{v}{f}$
where v is the wave speed and f is its frequency.

The speed of sound in air is v=344 m/s. The lowest frequency is f=20.0 Hz, so the corresponding wavelength is
$\lambda_1 = \frac{v}{f_1}= \frac{344 m/s}{20.0 Hz}=17.2 m$
The highest frequency is $f_2 = 2.00 \cdot 10^4 Hz$ , so the corresponding wavelength is
$\lambda_2 = \frac{v}{f_2}= \frac{344 m/s}{2.00 \cdot 10^4 Hz}=0.017 m$

Therefore, the range of wavelengths of audible sound in air is
[0.017 m - 17.2 m]

4 0

3 years ago

A 450.0 N, uniform, 1.50 m bar is suspended horizontally by two vertical cables at each end. Cable A can support a maximum tensi

bogdanovich [222]

Answer:

1) $W_{object} = 400 N$

2) x = 0.28 m from cable A.

Explanation:

1 ) Let's use the first Newton to find the , because bar is in equilibrium.

$\sum F_{Tot} = 0$

In this case we just have y-direction forces.

$\sum F_{Tot} = T_{A}+T_{B}-W_{bar}-W_{object} = 0$

Now, let's solve the equation for W(object).

$W_{object} = T_{A}+T_{B}-W_{bar} = 550 +300 - 450 = 400 N$

2 ) To find the position of the heaviest weight we need to use the torque definition.

$\sum \tau = 0$

The total torque is evaluated in the axes of the object.

Let's put the heaviest weight in a x distance from the cable A. We will call this point P for instance.

First let's find the positions from each force to the P point.

$L = 1.50 m$ ; total length of the bar.

$D_{AP} = x$ ; distance between Tension A and P point.

$D_{BP} = L-x$ ; distance between Tension B and P point.

$D_{W_{bar}P} = \frac{L}{2}-x$ ; distance between weight of the bar (middle of the bar) and P point.

Now, let's find the total torque in P point, assuming counterclockwise rotation as positive.

$\sum \tau = T_{B}(L-x)-T_{A}(x)-W_{bar}(\frac{L}{2}-x) = 0$

Finally we just need to solve it for x.

$x = \frac{T_{B}L-W_{bar}(L/2)}{T_{B}+W_{bar}+T_{A}}$

$x = 0.28 m$

So the distance is x = 0.28 m from cable A.

Hope it helps!

Have a nice day! :)

8 0

4 years ago

If I measure the current to be 0.5 A and the voltage is 4.5 V. What is my Power?

Korvikt [17]

As we know that P=IV so P = (0.5A)(4.5V)
P= 2.25 watt

6 0

3 years ago

How are passengers affected when a moving bus is stopped suddenly? Explain with reason.<br>

Mademuasel [1]

Answer:

When a moving bus stops suddenly, the passenger are pushed forward because of the inertia of the passengers. ... Because the lower part of the body comes to rest with the bus while the upper part tends to continue its motion due to inertia.

Explanation :

The passengers in a bus tend to fall backward when it starts suddenly due to inertia as the passengers tend to remain in the state of rest while the bus starts to move. When the bus stops suddenly, people fall forward because their inertia as they are in state of motion even when the bus has come to rest.

Hope this helps!! <3

Please mark as branliest

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2 years ago

A golfer strikes a golf ball with an initial velocity of 50 m/s at an angle of 35° to the horizon.

avanturin [10]

Answer:

for X, it's 50 times cos 35.

for y, it's 50 times sin 35.

5 0

3 years ago