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Mariana [72]
3 years ago
9

Which of the following statements is most closely associated with Einstein's general theory of relativity?

Physics
2 answers:
Fudgin [204]3 years ago
7 0
The answer is the first one. That's because the general theory of relativity is the thing experiencing whatever is experiencing relative to something else. The second answer is just plain wrong. The third answer is just a constant, and doesn't relate to experiencing anything. And the fourth answer is a force between two objects, and it has no second comparison. The first answer is how a subject experiences two different things.
Novosadov [1.4K]3 years ago
3 0

Answer:

Being in an accelerated frame is indistinguishable from experiencing gravity.

Explanation:

The general theory of relativity is the geometric theory of gravitation that describes it in modern physics. It generalizes the gravity as a geometric property of the space and time, or spacetime.

One of the principles of this theory is the equivalence principle, which states that the gravitational force experienced at a stade mode have no difference of the pseudo-gravity experienced in an accelerated frame, if the referential is a massive body, such as Earth.

Mass is not equivalent to weight, because weight is a force, which is the mass multiplied by the gravity acceleration; the other two statements come from Newton's gravitational theory.

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B, refraction I believe.
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Why does air blows from one place to another​
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Air blows from one place to another because gases move from high-pressure areas to low-pressure areas

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it happens because of pressure differences.

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Read 2 more answers
A racquetball strikes a wall with a speed of 30 m/s and rebounds in the opposite direction with a speed of 26 m/s. The collision
Fudgin [204]

Answer:

The average acceleration of the ball during the collision with the wall is a=2,800m/s^{2}

Explanation:

<u>Known Data</u>

We will asume initial speed has a negative direction, v_{i}=-30m/s, final speed has a positive direction, v_{f}=26m/s, \Delta t=20ms=0.020s and mass m_{b}.

<u>Initial momentum</u>

p_{i}=mv_{i}=(-30m/s)(m_{b})=-30m_{b}\ m/s

<u>final momentum</u>

p_{f}=mv_{f}=(26m/s)(m_{b})=26m_{b}\ m/s

<u>Impulse</u>

I=\Delta p=p_{f}-p_{i}=26m_{b}\ m/s-(-30m_{b}\ m/s)=56m_{b}\ m/s

<u>Average Force</u>

F=\frac{\Delta p}{\Delta t} =\frac{56m_{b}\ m/s}{0.020s} =2800m_{b} \ m/s^{2}

<u>Average acceleration</u>

F=ma, so a=\frac{F}{m_{b}}.

Therefore, a=\frac{2800m_{b} \ m/s^{2}}{m_{b}} =2800m/s^{2}

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3 years ago
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The pathway for you to be able is in your room you need
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2 years ago
A 2011 Porsche 911 Turbo S goes from 0-27 m/s in 2.5 seconds. What is the car's acceleration?
Natalka [10]

Answer:

-10.8m/s^2

Explanation:

a=change in velocity/change in time

-27 m/s/2.5=10.8m/s^2

or if its not negative

27m/s/2.5=10.8m/s^2

3 0
2 years ago
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