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3 years ago

25 miles/hour represents a

1 answer:

4 0

This would actually represents how the distance expands over the period of time. So, when this shows us that, this person or this thing went 25 miles in 4 hours, this would show us the acceleration of this car and he speed that this car or object would contain.

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Atoms in a solid are in continuous vibrational motion due to thermal energy. At room temperature, the amplitude of these atomic

Bingel [31]

Answer:

10 m/s

Explanation:

Given:

Amplitude of atomic vibrations (λ) = 10⁻⁹ cm = 10⁻⁹ × 10⁻² m = 10⁻¹¹ m [1 cm = 10⁻² m]

Frequency of the vibrations (f) = 10¹² Hz

In order to find the atom's maximum speed, we need to make use of the formula that relates speed, frequency and wavelength of the vibration.

Therefore, the formula for maximum speed is given as:

$v=f\lambda$

Now, plug in the values given and solve for speed 'v'. This gives,

$v=(10^{12}\ Hz)(10^{-11}\ m)\\\\v=10^{12-11}\ m/s\\v=10\ m/s$

Therefore, the atom's maximum speed due to thermal energy provided is 10 m/s.

6 0

4 years ago

The impulse given to a ball with mass of 2 kg is 16 N*s. If the ball starts from rest, what is its final velocity?

Alik [6]

The impulse is equal to the variation of momentum of the object:
$I=\Delta p = m \Delta v$
where m is the mass object and $\Delta v = v_f - v_i$ is the variation of velocity of the object.

The ball starts from rest so its initial velocity is zero: $v_i=0$ . So we can rewrite the formula as
$I=m v_f$
or
$v_f = \frac{I}{m}$

and since we know the impulse given to the ball (I=16 Ns) and its mass (m=2 kg), we can find the final velocity of the ball:
$v_f = \frac{16 Ns}{2 kg}= 8 m/s$

7 0

3 years ago

Read 2 more answers

What term is used for a weather condition characterized by lack of precipitation over a long period of time?

Marrrta [24]

Answer:

Explanation:

<h2>Drought</h2>

4 0

3 years ago

Read 2 more answers

A state in which all of the electrons in an atom have their lowest possible energies.

AnnZ [28]

If an atom, ion, or molecule is at the lowest possible energy level, it and its electrons are said to be in the ground state. If it is at a higher energy level, it is said to be excited, or any electrons that have higher energy than the ground state are excited.

6 0

3 years ago

A cannon fires a cannonball forward at a velocity of 48.1 m/s horizontally. If the cannon is on a mounted wagon 1.5 m tall, how

GalinKa [24]

Answer: 473.640 m

Explanation:

This situation is related to projectile motion or parabolic motion, in which the travel of the cannonball has two components: x-component and y-component. Being their main equations as follows:

x-component:

$x=V_{o}cos\theta t$ (1)

Where:

$V_{o}=48.1 m/s$ is the cannonball's initial velocity

$\theta=0$ because we are told the cannonball is shot horizontally

$t$ is the time since the cannonball is shot until it hits the ground

y-component:

$y=y_{o}+V_{o}sin\theta t-\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=1.5m$ is the initial height of the cannonball

$y=0$ is the final height of the cannonball (when it finally hits the ground)

$g=9.8m/s^{2}$ is the acceleration due gravity

We need to find how far (horizontally) the cannonball has traveled before landing. This means we need to find the maximum distance in the x-component, let's call it $X_{max}$ and this occurs when $y=0$ .

So, firstly we will find the time with (2):

$0=1.5 m+48. 1 m/s sin(0\°) t-(4.9 m/s^{2})t^2$ (3)

Rearranging the equation:

$0=-(4.9 m/s^{2})t^2+48. 1 m/s sin(0\°) t+1.5 m$ (4)

$-(4.9 m/s^{2})t^2+(48. 1 m/s) t+1.5 m=0$ (5)

This is a quadratic equation (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula: