Answer:
Frictional force increases with the increase in the roughness of the surface.
Explanation:
You will see that the rougher the surface, the greater the wear and tear.
Answer:
Time - taken = 2.5 s
deceleration= -8 m/s²
Solution:
Given:
speed, v = 8 m/s
distance, d = 20m
To Find:
deacceleration = ?
As we know speed is defined as
v = d/t
plugging in the values
t = 20/ 8
t = 2.5s
Now from deceleration formula
a = - v/ t
a = - 20/ 2.5
a = - 8 m/s²
Thus, the time taken and acceleration is 2.5 s and -8 m/s²
respectively.
Learn more about deceleration here:
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Answer: It will push back with an equal amount of force.
Answer:
w = 0.886 rad / s
Explanation:
Angular and linear variables are related
a = α r
where a is the linear acceleration, α the angular acceleration and r the radius of gyration
α = a / r
the angular velocity we can find it
w² = w₀² + 2 α θ
the initial angular velocity is zero, the angles to be horizontal is
θ = π/ 2 rad
we substitute
w = √ 2 a / r θ
we calculate
w = √ (2 3/12 π/2)
w = 0.886 rad / s
