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algol [13]
2 years ago
14

Why cant you see individual atoms without a special tool​

Chemistry
2 answers:
lesya692 [45]2 years ago
6 0

Answer:

its because atoms are incredibly small its looking for atoms is like placing a blueberry in a foot ball field and looking at it from 10 miles up you cant see that blueberry

Explanation:

Anton [14]2 years ago
6 0

Answer:

They are astronomically small and are unable to been seen with the naked eye.

Explanation:

Atoms are what make up all of matter.

You might be interested in
7. Some of the following sublevels do not exist. Cross out the ones that are not real.
zubka84 [21]

Answer:

1f 3f 5g 1p 2d

Explanation:

There is only 4f and 5f orbitals.

G is not an orbital.

P orbital starts with 2p

D orbital starts with 3d

7 0
3 years ago
I really need help with this I would really appreciate it​
gulaghasi [49]
PV=nRT will give you the answer I think. I haven’t worked with a certain unit in that problem
3 0
3 years ago
How many molecules are present in 2 H₂ SO4​
fomenos

Answer:

in H2So4 splits in 2 H+ and a

so42 -particle=3particle per mole.So2

moles H2So4 will result in 3*2=6moles

of molecules.

5 0
2 years ago
Read 2 more answers
Explain what would happen in Step 2 if the cylinder were heated with the plunger held steady.
Svetradugi [14.3K]

Answer:

be more descriptive

Explanation:

4 0
3 years ago
The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate
vovangra [49]

Answer:

K2 = 61.2 M^-1.S^-1

Explanation:

We complete the question fully:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0kJ/mol . If the rate constant of this reaction is 6.7M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

Answer is as follows:

The question asks us to calculate the value of the rate constant at a certain temperature, given that it is at a particular value for a particular temperature. We solve the question as follows:

According to Arrhenius equation, the relationship between temperature and activation energy is as follows:

            k = Ae^-(Ea/RT)

where,   k = rate constant

              A = pre-exponential factor

          Ea  = activation energy

             R = gas constant

              T = temperature in kelvin

From the equation, the following was derived for a double temperature problem:

ln(k2/k1) = (-Ea/R) * (1/T1 - 1/T2)

We list out the parameters as follows:

         

      T1= (244 + 273.15) K = 517.15 K

      T2= (324+ 273.15) K =597.15 K

    K1  = 6.7 ,     K2 = ?

         R = 8.314 J/mol K

     Ea = 71.0 kJ/mol = 71000 J/mol

Putting the given values into the above formula as follows:

ln(k2/6.7) = (-71000/8.314) * (1/517.15 - 1/597.15)

lnk2 - 1.902 = 8539.8 * 0.000259

lnK2 = 1.902 + 2.21

lnK2 = 4.114

K2 = e^(4.114)

K2 = 61.2

Hence, K2 = 61.2 (M.S)^-1

7 0
3 years ago
Read 2 more answers
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