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ExtremeBDS [4]
3 years ago
7

10 points...............

Mathematics
2 answers:
Alisiya [41]3 years ago
7 0
I think the one that's gray that's the correct answer.Hope this helps! ;)
swat323 years ago
7 0

Answer:

Quadratic is the correct answer.

Step-by-step explanation:

Have a great day!

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Erin writes the set of ordered pairs below. The set represents a function.
tino4ka555 [31]
Point A shows that she is incorrect.
With functions, you can perform the "straight line test through each point. If the line goes through both points, you know it's not a function.
If we plotted point A, it'd fail the straight line test because the given point (-6, 7) already has -6 as an x value.
Hope this helps!
7 0
3 years ago
2a) Solve using substitution.
Tcecarenko [31]
First things first, write out your equation without the substitution.

2x+ 2y= 10

Now, put in the substitution.

2x+ 2• 2= 10

Combine like terms.

2x+ 4= 10

Now that your equation it simplified, you need to reverse the problem and put everything on the other side.

2x+ 4= 10
- 4 - 4
2x = 6

2x=6
— —
2 2

X= 3

So the final answer is x=3

8 0
3 years ago
You are given a list of students names and their test scores. Design a pseudocode that does the following:(a) Calculates the ave
Rashid [163]

Answer:

List_of_students = {};    //Structure array that contains the scores of students and Names

Number_of_students = size(List_of_students);

Average_score ;   //Variable Stores average score

Below_Average = [];   //That is initially filled with zeros  

Highest_score ; //Initialize variable to store highest score

for ( i = 0 ; i < Number_of_students; i = i + 1)

{

      Average_score  = Average_score + List_of_students(i);    

     if ( i = 15)

      {

        Average_score  = Average_score / Number_of_students;

      }

}

for ( j = 0; j < Number_of_students ; i = i + 1)

{

    if (   List_of_students(j)  < Average_score)

     {

         print( "student  %name got %score , List_of_students(j),          List_of_students(j) )

     }

}

Compare_Score = 0;   //Variable to compare score

for ( k = 0; K < Number_of_students; k = k+1)

{

     if ( List_of_students(k) => Compare_Score)

    {

        Compare_Score = List_of_students(k);

    }

}

Highest_Score = Compare_Score;

Step-by-step explanation:

4 0
3 years ago
The range of 16,23,55,64,49
miskamm [114]

Answer: 48

Step-by-step explanation: To find the range of the data set shown here, remember that the range is the difference between the greatest number in the data set and the least number in the data set.

<em>Greatest number</em> → 64

<em>Least number → </em>16

Now, we need to subtract 16 from 64.

64 - 16 = 48

Therefore, the range of the data set is 48.

7 0
3 years ago
How to do this problem. I need help <br> How to solve the e
Radda [10]
The answer is  6*2-6. I hope this helps u

5 0
4 years ago
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