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allsm [11]
3 years ago
5

A 125 kg linebacker runs to the right at 2.5 m/s and an 80 kg quarterback runs to the left at 3 m/s. They collide in midair and

the linebacker holds on to the quarterback so they move off together. What is their velocity (magnitude and direction) immediately after this collision
Physics
1 answer:
Alexxx [7]3 years ago
6 0

Answer: 0.35 m/s to the right.

Explanation:

Let's define M1 and V1 as the mass and velocity of the linebacker, and define the right as the positive side.

M1 = 125kg

V1 = 2.5m/s

M2 and V2 as the velocity and mass of the quarterback.

M2 = 80kg

V2 = -3m/s

where V2 has a minus sign because the quarterback is running to the left.

We know that after the collision, both players keep stick togheter, so we can think this as an perfectly inleastic collision, where the velocity of both players can be obtained by:

v = (M1*V1 + M2*V2)/(M1 + M2) = (125kg*2.5m/s - 80kg*3m/s)/(125kg + 80kg)

v = (72.5/205) m/s = 0.35m/s

Because this velocity is positive, this means that both players are moving to the right.

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How do stars serve as evidence for the expansion of the universe and the Big Bang theory?​
castortr0y [4]

Answer:

The Doppler red-shift of light observed from distant stars and galaxies gives evidence that the universe is expanding (moving away from a central point). This allows for Big Bang Theory, because after a “bang” occurs all of the matter moves away from the point of origin.

7 0
4 years ago
Block on inclined plane experience a force due to gravity of 300N straight down. If the slope is inclined at 67.8°to the horizon
Tems11 [23]

Answer:

The component of the force due to gravity perpendicular and parallel to the slope is  113.4 N and 277.8 N respectively.

Explanation:

Force is any cause capable of modifying the state of motion or rest of a body or of producing a deformation in it. Any force can be decomposed into two vectors, so that the sum of both vectors matches the vector before decomposing. The decomposition of a force into its components can be done in any direction.

Taking into account the simple trigonometric relations, such as sine, cosine and tangent, the value of their components and the value of the angle of application, then the parallel and perpendicular components will be:

  • Fparallel = F*sinα =300 N*sin 67.8° =300 N*0.926⇒ Fparallel =277.8 N
  • Fperpendicular = F*cosα =  300 N*cos 67.8° = 300 N*0.378 ⇒ Fperpendicular= 113.4 N

<u><em>The component of the force due to gravity perpendicular and parallel to the slope is  113.4 N and 277.8 N respectively.</em></u>

6 0
3 years ago
PLEASE ANSWER ASAP!!!!!!!
Viefleur [7K]

Answer:

B. Mechanical energy= 50J+30J=80J

4 0
3 years ago
Calculate the G.P.E. in joules of a 675-newton climber at the top of a 3,050-meter mountain in Colorado.
almond37 [142]

Answer:2673

Explanation:

4 0
3 years ago
O
Sergio [31]

see

below

Explanation:

refractive index = speed of light in vacuum / speed of light in medium

light travels at a speed of 3.0 x 10^8 m/s in vacuum

refractive index = 3.0 x 10^8 / 2.0 x 10^8

refractive index = 1.5

hope this helps, please mark it

4 0
3 years ago
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